Question

Solve for x use the completing the square method x^2+6x=5

Answer 1

Answer:

x=−3±√14

Hope this helps!

Answer 2

Answer:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

Step-by-step explanation:

$x^{2}$+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

$x^{2}$+6x+9-9-5=0

we have:

$(x+3)^{2}$-9-5=0

$(x+3)^{2}$ = 14

lets apply square root on both sides of the equation:

$\sqrt{(x+3)^{2}}=\sqrt{14}$

we know:

$\sqrt{a^{2}} = abs(a)$

so we have:

abs(x+3)=$\sqrt{14}$

from where two solutions are obtained

$x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}$

finally we have:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$