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3 years ago

Which of the following angles are congruent to 6? select all that apply.

Mathematics

1 answer:

sveta [45]3 years ago

8 0

Answer:

which of the following angles are congruent to 6? select all that apply.

A. 1

B. 3

C. 2

D. 4

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What's the property that justifies my 1st step?

rusak2 [61]

Substraction is a comutative operation
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4x + 4 = 72
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x = 68 / 4
x = 17.

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4 years ago

Explain why d= a + c. in a triangle

rewona [7]

Answer:

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3 years ago

The figure shown is a regular octagon. The measure of What is the measure of

emmainna [20.7K]

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2 years ago

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Please help me with this

Vera_Pavlovna [14]

Answer:

226.19

Step-by-step explanation:

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4 years ago

5+ 3 cos ½x = 7 how to find the x?

Anon25 [30]

Answer:

$x=\pm 2 arcos(\frac{2}{3})+4k\pi$

where $k$ is an integer

Step-by-step explanation:

$5+3\cos(\frac{1}{2}x)=7$

We are going to isolate the trig expression first.

Subtract 5 on both sides:

$3\cos(\frac{1}{2}x)=2$

Divide both sides by 3:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

Now since $\cos(u)$ is even then $\cos(u)=\cos(-u)$ .

So we have:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

implies:

$\frac{1}{2}x=arccos(\frac{2}{3})+2k\pi$

Multiply both sides by 2:

$x=2arccos(\frac{2}{3})+4k\pi$

$-\frac{1}{2}x=arcos(\frac{2}{3})+2k\pi$

Multiply both sides by -2:

$x=-2arccos(\frac{2}{3})-4k\pi$

So we can say the solution is:

$x=\pm 2arcos(\frac{2}{3})+4k\pi$

( $k$ is an integer)

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3 years ago