Answer:
2) -141 hits/da
Step-by-step explanation:
Calculate the values of h(2) and h(4)
h(2) = 2170(0.92)² = 2170 × 0.8464 = 1837
h(4) = 2170(0.92)⁴ = 2170 × 0.7164 = 1555
Calculate the average rate of change
Rate of change = (y₂ - y₁)/(x₂-x₁) = (1555 -1837)/(4 - 2) = -282/2 = -141 hits/da
The average rate of change is -141 hits/da.
In the figure below, the red curve represents the function h(d), while the green dashed line represents the average rate of change over the interval 2 ≤ d ≤4.
Answer:
The solution is 12. The equation is (115 - 19) ÷ 8.
Step-by-step explanation:
We can solve this problem by using division.
First, let's take away 19.
115 - 19 = 96
Now let's divide 96 by 8.
96 ÷ 8 = 12.
And we have 12, our answer.
Let f(b) = <span>3b^2+13b+4/b+4
</span>the domain of f is D = {b/ b+4#0} so b# - 4
so the undefined value of is when b = -4
Answer:
Last week, she earned a total of $702 last week in commission.
Step-by-step explanation:
To solve this, we first need to find 13% of $5,400.
5,400 x 0.13 = 702
Therefore, Nadia earned a total of $702 last week in commission.
Now, we need to calculate how much money she'll earn in a whole year. So, let's see how many weeks are in a year.
1 year = 52 weeks when rounded to the nearest whole number
702 x 52 = $36,504
Therefore, Nadia earned a total of $36,504 in commission in 2011.
Hope this helps! :D
Answer:
a) $432
b) (i) $8970
Step-by-step explanation:
Given that:
Ratio of Cost of Hansi and Megan is 7 : 4.
Hansi's holidays cost = $756
Hansi's earnings in 2008 = $7800
In 2009, there are 15% more earnings than in 2008.
To find:
Cost of Megan's holiday.
Earnings in 2009 ?
Solution:
As per given question statement,
Let the holiday cost of Hansi = 7
Let the holiday cost of Megan = 4
As per question statement:

We have to find the value of 4
now.

b)(i)
Earnings in 2009:
$7800 + 15% of $7800
