The word algebra originate from baghdad.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
a. 3, 100 degrees
- I know 6 is 100 degrees and angle 3 is identical to angle 6. Therefore, angle 3 is 100 degrees.
b. 6, 100 degrees
- Angle 3 and 6 are identical. This means angle 6 is 100 degrees.
c. 4, 80
- Knowing a straight line is 180 degrees and all other angles are 100 degrees, I subtracted 180-100 = 80 degrees
Step-by-step explanation:
Everything was explained above, but be sure to know...
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- Hope that helps! Please let me know if you need further explanation.
See the graph below
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Explanation:</h2><h2>
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A polynomial function whose degree is 4 is given by the form:
Here the roots are:
If we set 
then:
Finally, by using graphing tool we get the graph of our polynomial function:
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Parabola: brainly.com/question/10618210
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Use trigonometry to find L.
Tangent = opposite over adjacent on any right triangle.
tan(L) = 18/23
Take the inverse on both sides.
arctan(tan(L)) = arctan(18/23)
L = 38.0470425318
L = 38.05°
Done.
