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2 years ago

Help ASAP giving BRAINLIEST! Am i correct?

Mathematics

2 answers:

drek231 [11]2 years ago

6 0

Answer:

Yes

Step-by-step explanation:

We have the inequality:

x-7 > 27

To solve this, we have to get by itself. 7 is being subtracted from x. To undo this, add 7 to both sides, since addition is the opposite of subtraction.

x-7+7>27+7

x>34

So, your answer is correct

murzikaleks [220]2 years ago

3 0

Answer:

The answer is yes

Step-by-step explanation:

x-7 > 27

x> 27 +7

x > 34

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3 years ago

Giving brainliest to first person hurry help!!

Artemon [7]

Answer: If you're looking for the sum of the equation, it's 9.57.

If you're looking for a better way to add it. It's this. (1.7 + 5.3) + 2.57.

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2 years ago

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Veseljchak [2.6K]

Answer:

The area of the rectangle TOUR is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

$Area\ of\ a\ Rectangle=length\times width$

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Considering the rectangle TOUR the area formula will be:

Area of Rectangle TOUR = TO × OU

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices T and O as:

$TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}$

Compute the distance between the vertices O and U as:

$OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}$

Compute the area of rectangle TOUR as follows:

$Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}$

Thus, the area of the rectangle TOUR is 80.00 unit².

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2 years ago

From the top of a tree a bird looks down on a field mouse at an angle of depression of 50 degrees if the field mouse is 40 M fro

Zepler [3.9K]

The tangent function gives the ratio of vertical to horizontal distance in this case.
.. vertical distance = (horizontal distance)*tan(angle of depression)
.. = (40 m)*tan(50°)
.. vertical distance ≈ 47.7 m

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