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3 years ago

6

Help ASAP giving BRAINLIEST! Am i correct?

2 answers:

drek231 [11]3 years ago

6 0

Answer:

Yes

Step-by-step explanation:

We have the inequality:

x-7 > 27

To solve this, we have to get by itself. 7 is being subtracted from x. To undo this, add 7 to both sides, since addition is the opposite of subtraction.

x-7+7>27+7

x>34

So, your answer is correct

murzikaleks [220]3 years ago

3 0

Answer:

The answer is yes

Step-by-step explanation:

x-7 > 27

x> 27 +7

x > 34

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What is the domain of this graph?

professor190 [17]

Answer:

B

Step-by-step explanation:

The answer is b because the domain of anything is always x or on the x axis .

7 0

3 years ago

Read 2 more answers

The half-life of a radioactive element is 130 days, but your sample will not be useful to you after 80% of the radioactive nu

gtnhenbr [62]

Answer:

We can use the sample about 42 days.

Step-by-step explanation:

Decay Equation:

$\frac{dN}{dt}\propto -N$

$\Rightarrow \frac{dN}{dt} =-\lambda N$

$\Rightarrow \frac{dN}{N} =-\lambda dt$

Integrating both sides

$\int \frac{dN}{N} =\int\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$\Rightarrow ln|N_0|=-\lambda .0+c$

$\Rightarrow c= ln|N_0|$

$\therefore ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$ .......(1)

$\frac{N}{N_0}=e^{-\lambda t}$ .........(2)

Logarithm:

$ln|\frac mn|= ln|m|-ln|n|$
$ln|ab|=ln|a|+ln|b|$

$ln|e^a|=a$

$ln|a|=b \Rightarrow a=e^b$
$ln|1|=0$

130 days is the half-life of the given radioactive element.

For half life,

$N=\frac12 N_0$ , $t=t_\frac12=130$ days.

we plug all values in equation (1)

$ln|\frac{\frac12N_0}{N_0}|=-\lambda \times 130$

$\rightarrow ln|\frac{\frac12}{1}|=-\lambda \times 130$

$\rightarrow ln|1|-ln|2|-ln|1|=-\lambda \times 130$

$\rightarrow -ln|2|=-\lambda \times 130$

$\rightarrow \lambda= \frac{-ln|2|}{-130}$

$\rightarrow \lambda= \frac{ln|2|}{130}$

We need to find the time when the sample remains 80% of its original.

$N=\frac{80}{100}N_0$

$\therefore ln|{\frac{\frac {80}{100}N_0}{N_0}|=-\frac{ln2}{130}t$

$\Rightarrow ln|{{\frac {80}{100}|=-\frac{ln2}{130}t$

$\Rightarrow ln|{{ {80}|-ln|{100}|=-\frac{ln2}{130}t$

$\Rightarrow t=\frac{ln|80|-ln|100|}{-\frac{ln|2|}{130}}$

$\Rightarrow t=\frac{(ln|80|-ln|100|)\times 130}{-{ln|2|}}$

$\Rightarrow t\approx 42$

We can use the sample about 42 days.

7 0

3 years ago

Consider independently rolling two fair dice, one red and the other green. Let A be the event that the red die shows 3 dots, B b

max2010maxim [7]

Answer:

A & B are independent events. A & C, B & C are not independent events.

Step-by-step explanation:

Independent Events are the events, whose occurrences are completely unrelated to each other.

Event A 'Red dice getting 3' & Event B 'Green die getting 4' ; are unrelated to each other. The numbers on red dice & on green dice are not dependent on each other.

Event C 'Red & Green dice numbers showing sum = 7' is dependent on the numbers coming on red & green dice , i.e events A & events B respectively. So, event C is dependent on both events A & B.

4 0

3 years ago

In a company, 65% of the workers are women. If 1820 people work for the company who are men, how many workers are there in a

snow_lady [41]

Answer:

women=x=65%

so men=100-65=35%=1820

let total workers be y

atq....y×35/100=1820=y=5200workers

8 0

3 years ago

I need Ans Fast !!!!!!!<br><br>

Alenkinab [10]

Step-by-step explanation:

A={6,9,11},B=ϕ

Here, B is empty set.

Therefore,

A∪B

=A∪ϕ

={6,9,11}

A intersection ϕ is ϕ I guess

6 0

3 years ago