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Salsk061 [2.6K]
3 years ago
9

Please help!! Will mark brainilest ☺️

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Because there's no change in x so it has to be a straight line going through the y-axis.

Also for A and C, they don't even touch y = 2 so you can easily cross those out.

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Answer each question about the following
DIA [1.3K]

Answer:

s=7/9

 i hope this help

3 0
3 years ago
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2/5 (x-4) =2x. Solve for x
Bess [88]
\dfrac{2}{5}(x-4)=2x\ \ \ \ |multiply\ both\ sides\ by\ 5\\\\2(x-4)=10x\ \ \ \ |use\ distributive\ property:a(b-c)=ab-ac\\\\2x-8=10x\ \ \ |add\ 8\ to\ both\ sides\\\\2x=10x+8\ \ \ \ |subtract\ 10x\ from\ both\ sides\\\\-8x=8\ \ \ \ |divide\ both\ sides\ by\ (-8)\\\\\boxed{x=-1}
7 0
3 years ago
Find the total surface area of this cone.<br> leave your answer in terms of pi<br> R=3<br> L=4
Yuliya22 [10]

Answer:

total surface area of cone is πr (r+l)

22/7 x 3 (3+4)

22/7*3 (7)

22 x 3 ( as 7 that was divided by 22 was cut out with 7 in the bracket)

hence,

TSA of cone = 66pi

8 0
3 years ago
Can some please answer this
Sonbull [250]

9514 1404 393

Answer:

  B  (2 violet)

Step-by-step explanation:

Let the colors be represented by their first letter. Then the balances give rise to two equation:

  o +y +b +v = r +g +b

  o +y +v = g +v

Subtracting the second equation from the first gives ...

  (o +y +b +v) -(o +y +v) = (r +g +b) -(g +v)

  b = r +b -v

Adding v-b to both sides, we have ...

  b +(v -b) = r +b -v +(v -b)

  v = r

Multiplying this result by 2, we can match the final balance:

  2r = 2v . . . . . . . choice B

7 0
2 years ago
Read 2 more answers
Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate
kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality x^{2}-5x+4\leq 0. To do that, factorize, then we have that (x-4)(x-1)\leq 0. This implies that

x-1\leq 0\, \text{and}\, x-4\geq 0

or

x-1 \geq 0\, \text{and}\, x-4\leq 0

In the first case the solution is the empty set \emptyset. In the second case the solution is the interval 1\leq x \leq 4. Now we have that

A=[1,4]

B=(3,5)

C=(3,4].

To show that A\cap B\subseteq C consider x\in A\cap B. Then 1\leq x \leq 4\, \text{and}\, 1, this implies that 3, then x\in C. Now, to show that C\subseteq A\cap B consider x\in C, then 3, then 1\leq x \leq 4\, \text{and}\, 3, then x\in [1,4] \, \text{and}\, x\in (3,5), this implies that x\in A\cap B.

Observe the image below.

7 0
3 years ago
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