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melisa1 [442]
3 years ago
12

A conical tent made of canvas has a base that is 34 feet across and a slant height of 12 feet. To the nearest whole unit, what i

s the area of the canvas, including the floor? Use 3.14 for π.
Mathematics
2 answers:
belka [17]3 years ago
6 0

Answer:

The area of the canvas, including the floor is 1548 sq. feet.          

Step-by-step explanation:

Given : A conical tent made of canvas has a base that is 34 feet across and a slant height of 12 feet.

To find : What is the area of the canvas, including the floor?

Solution :  

A conical tent made of canvas has a base that is 34 feet.

The diameter of the base is D=34 feet.

The radius of the base is r=\frac{34}{2}=17

The slant height l=12

The area of the canvas, including the floor is

A=\pi r l+\pi r^2

A=\pi r(l+r)

A=3.14\times 17(17+12)

A=3.14\times 17\times29

A=1548.02

In nearest whole unit, A=1548 sq. feet.

Therefore, The area of the canvas, including the floor is 1548 sq. feet.

tresset_1 [31]3 years ago
4 0
Here you'll need to do some online research, using "area of a cone" as your search term.  There is a formula!  But it's complicated.

Once you've found this formula online, substitute 17 feet for r.  The height of the cone has to be calculated from the slant height (these are not the same):

(slant height)^2 = (12 feet)^2 = r^2 + h^2, where h is the actual height of the cone.

The area of the base is pi*r^2, or pi*17^2 square feet.
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1 year ago
Calculate the perimeter for the parallelogram if a= 7.6 , b= 5.9 and c= 14.6
kolezko [41]

Although the problem gives the value of b, it's really not needed.

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Somebody please explain this I have a major exam soon and I really need to know how to solve problems like this​
nevsk [136]

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Step-by-step explanation:

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3 years ago
Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

X(1, 2) = (x_2, y_2)

Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

WX = \sqrt{(2)^2 + (1)^2}

WX = \sqrt{4 + 1}

WX = \sqrt{5}

WX = 2.24

✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

XY = \sqrt{(1)^2 + (-6)^2}

XY = \sqrt{1 + 36}

XY = \sqrt{37}

XY = 6.08

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

Y(2, -4) = (x_1, y_1)

Z(-2, -1) = (x_2, y_2)

Plug in the values

YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}

YZ = \sqrt{(-4)^2 + (3)^2}

YZ = \sqrt{16 + 9}

YZ = \sqrt{25}

YZ = 5

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

W(-1, 1) = (x_2, y_2)

Plug in the values

ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}

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ZW = \sqrt{1 + 4}

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✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

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