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Viefleur [7K]
3 years ago
15

The cost of 5 pens is $140.50. What is the cost of 1 pen?

Mathematics
2 answers:
yuradex [85]3 years ago
8 0

Answer:

$28.1

Step-by-step explanation:

Divide

140.50 divided by 5 = 28.1

(That's an expensive pen)

nydimaria [60]3 years ago
5 0

Answer:

28.1

Step-by-step explanation:

140.50/5

These are some expensive pens

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Mice21 [21]

Answer:

  c = 92/n

Step-by-step explanation:

The equation that describes the inversly proportional relationship is ...

  y = k/x

The value of the constant of proportionality can be found from ...

  xy = k . . . . . . product of values of independent and dependent variables

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In this problem, we have c = 23 for n = 4, so the constant of proportionality is ...

  k = c×n = (23)(4) = 92

The equation for the relationship is ...

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2 years ago
In need to know what is the solution of the equation 101.4 - d = 99.2
Grace [21]
The solution is d = 2.2
6 0
3 years ago
Read 2 more answers
Multiply Conjugates Using the Product of Conjugates Pattern
SpyIntel [72]

Answer:

The product is the difference of squares is $$\left(11-b\right)\left(11+b\right)=121-{{b}^2}$$

Step-by-step explanation:

Explanation

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  • We have to multiply the given expression.
  • Square the first term 11. Square the last term b.

$$\begin{aligned}&(11-b)(11+b)=(11)^{2}-(b)^{2} \\&(11-b)(11+b)=121-b^{2}\end{aligned}$$

5 0
2 years ago
2/5x+1/4x=26 what is x
shepuryov [24]

Answer:

x = 40

Step-by-step explanation:

2/5x + 1/4x = 26

~Find common denominators

8/20x + 5/20x = 26

~Combine like terms

13/20x = 26

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x = 40

Best of Luck!

6 0
3 years ago
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4tan^(2)x-(4)/(cotx)+sinxcscx 


To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 


4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin... 


Complete the multiplication to produce a denominator of cotx in each expression. 

(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot... 


Combine the numerators of all expressions that have common denominators. 
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(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
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