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romanna [79]
4 years ago
12

By how much does the median of the data set 12, 9, 9, 11, 14, 28 change if the outlier is removed?

Mathematics
1 answer:
Semenov [28]4 years ago
6 0

Hi there! Here's the answer and how I got that answer!!

Answer:

<u><em>11</em></u>

<em>The change in the Median would be 11 instead of 11.5 because the total amount of numbers became odd when the outlier is removed. This allowed for the step of having to solve for two middle numbers to be avoided and therefore only leave you with the answer simple as 11 instead of having to solve between two numbers!</em>

Step-by-step explanation:

With all the numbers (including the outlier) the median would be 11.5.

<u>Here's how:</u>

First sort least to greatest and cancel out the numbers until you get to the one on the middle.

9, 9, <u>11, 12</u>, 14, 28

If you have <em>two</em> middle numbers add them together and then divide by two.

11+12=23

23/2= 11.5

So your median <u>with</u><em> </em>the outlier is 11.5.

Now if you take out the outlier, which in this case I'm assuming its 28. Let's re-look for the median once more!

First sort least to greatest and cancel out the numbers until you get to the one on the middle.

9, 9, <u>11</u>, 12, 14

Now because there is an odd amount of numbers your left to only <em>one middle number,</em> 11.

<u>This means if the outlier is removed the median would change to be </u><u>11</u><u>.</u>

I hope this helps, have a stupendous day!! ☆*:.。.o(≧▽≦)o.。.:*☆

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