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SashulF [63]
3 years ago
8

What is the absolute value of -3? 3 - 1/3 -3 1/3

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0
The absolute value of -3 is 3 and -3 so both would be right
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Each day of the week mrs uses 3/4 of a gallon of gas what is the amount she uses in five days?
Andrej [43]

Answer:

3.75

Step-by-step explanation:

3/4 times 5 =3 3/4

8 0
1 year ago
Find the perimeter of a square that is 3inches on a side. 7 inches 15 inches 12 inches 30 inches
In-s [12.5K]

Answer:

12 inches

Step-by-step explanation:

A square has 4 sides with the same length.

The perimeter of a square is the 4 times the length of one side.

perimeter = 4s

perimeter = 4 * 3 inches

perimeter = 12 inches

4 0
3 years ago
Read 2 more answers
the measure of two angles of a triangle are 35 and 45 what is the measure of the third angle of the triangle
loris [4]
 <span>If you pull the edges of the right angle down it makes a straight line. 

Therefore, the angles in a triangle add up to 180° 

So, 35 + 45 = 80 

Then, 180 - 80 = 100 

The third angle = 100° </span>
4 0
3 years ago
Read 2 more answers
Need Help with this question
Fantom [35]
82
The sum of the three angles is 180. One is given and the other we can figure out because it forms a straight line (180) with the angle to the left outside. The outside angle is 117, so 180-117 is 63.
So then add up the 3 angles in the triangle
63+35+y=180
y= 82
3 0
3 years ago
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}&#10;\\ \quad \\&#10;\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\&#10;-----------------------------\\\\&#10;\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}&#10;\\\\\\&#10;\textit{now taking }sin^{-1}\textit{ to both sides}&#10;\\\\\\&#10;sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)&#10;\\\\\\&#10;\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
8 0
3 years ago
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