What is the absolute value of -3?<br><br><br> 3<br>

you are making beaded bracelets for your for your friends. you want to use 30 beads for each bracelet want to use no more than 1

Softa [21]

30(x)<=145 and yes she would be able to make 4 bracelets because 30 x 4 = 120 and that is less than 145

5 0

3 years ago

The number of miles driven by a truck driver falls between 300 and 700, and follows a uniform distribution.

Elena-2011 [213]

Answer:

(A) 0.125 probability

(B) 0.625 probability

(C) 660 miles

Step-by-step explanation:

The distance driven by a truck driver daily, falls between 300miles and 700miles and follows a uniform distribution.

(A) The probability that the truck driver goes more than 650 miles a day is:

[700 - 650] / [700 - 300] = 50/400 = 0.125

(B) The probability that the truck driver goes between 400 and 650 miles a day is:

[650 - 400] / [700 - 300] = 250/400 = 0.625

(C) The minimum number of miles the truck driver travels on the furthest 10% of days is given thus:

10% of 400 = 40

Subtract this from the farthest distance;

700miles - 40miles = 660miles

7 0

2 years ago

What are both of the ranges

MArishka [77]

Answer:

0.8 < x < 16.8

Step-by-step explanation:

The third side of the triangle is always less than the other two sides combined. I think of it like if it was greater than the other two sides added, there would be no triangle- it'd be a line.

The other rule is that it has to be greater than the difference between the two lines.

I hope this helped!

6 0

3 years ago

-9 x 1/3 equals ___________________________

Leno4ka [110]

-9 x 1/3
= -9/3
= -3
......................................

8 0

3 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

What is the absolute value of -3? 3 - 1/3 -3 1/3