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dlinn [17]
3 years ago
10

HELP FAST

Mathematics
1 answer:
evablogger [386]3 years ago
7 0

Answer:

  D)  5/12

Step-by-step explanation:

Suppose there are 30 girls at the school. Then the proportions tell you that 12 of them study music, and 5 of them study both music and dance.

Then 5 of the 12 girls who study music also study dance. That fraction is 5/12.

_____

We chose 30 because it is the least common multiple of the denominators of the fractions (2/5, 3/5, 1/6) in the problem statement.

Of course, you know that 2/5·30 = 12, and 1/6·30 = 5.

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Which system of equations can be used to find the roots of the equation 4x2 =x3 +2x?
ra1l [238]

Answer:


<h2>\left \{ {{y=4x^2} \atop \\ \\ {y=x^3+2x}} \right.</h2>

Explanation:


An equality can be transformed in a system of equations by making each side equal to a new variable. In this case the variable y was made equal to each side.


See that may find the solution of such system by graphing both functions in a same coordinate system, where the intersection of the functions would show the solution of the system.


I show you that in the attached image. In such graph, the red curve is the function y = x² and the blue function is y = x³ + 2x.


The intersection point is (0,0) meaning that the solution is x = 0, y = 0.



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Solve the following... <br><img src="https://tex.z-dn.net/?f=3%28x%2B2%29%3D-5-2%28x-3%29" id="TexFormula1" title="3(x+2)=-5-2(x
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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

\qquad \sf  \dashrightarrow \: 3(x + 2) =  - 5 - 2(x - 3)

\qquad \sf  \dashrightarrow \: 3x + 6 =  - 5 - (2x - 6)

\qquad \sf  \dashrightarrow \: 3x + 6 =  - 5 - 2x + 6

\qquad \sf  \dashrightarrow \: 3x  + 6 =   - 2x + 1

\qquad \sf  \dashrightarrow \: 3x + 2x = 1 - 6

\qquad \sf  \dashrightarrow \: 5x =  - 5

\qquad \sf  \dashrightarrow \: x =  - 5 \div 5

\qquad \sf  \dashrightarrow \: x =  - 1

4 0
1 year ago
How can I make sure that each point of a Triangle was reflected across the line?
larisa86 [58]

For example, for A and A'

Let:

R=(0,0) the reference point:

\begin{gathered} \text{Distance between A and R:} \\ d=\sqrt[]{(4-0)^2+(2-0)^2}=2\sqrt[]{5} \\ \text{Distance between A' and R} \\ d=\sqrt[]{(4-0)^2+(-2-0)^2}=2\sqrt[]{5} \end{gathered}

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