Answer:
A example: A customer brought 5 quarts of lemonade from Leah's stand. She also tipped Leah an additional $2. The customer finally paid a total of $27 including the tip. How much is each quart of lemonade worth? If x is what the lemonade is worth, write an equation to figure out the total.
In this problem, the x is what the lemonade is worth. So you should start with a 5x. The customer also tipped $2. So you should add 2 to the 5x. We also know the total, 27.
With the information we can form an equation.
5x + 2 = 27.
To solve, we can subtract 2 from both sides and finally dived by 5 on both sides as well. Your final answer should be x = 5.
Hopefully this is what you're looking for, sorry for being late!
Answer: 6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.
step by step explanation:
\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}
Solution-
The quadratic function is,
6x^2-24x + 1
a = 6, b = -24, c = 1
x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}
=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}
=\dfrac{24\pm \sqrt{576-24}}{12}
=\dfrac{24\pm \sqrt{552}}{12}
=\dfrac{24\pm 2\sqrt{138}}{12}
=\dfrac{12\pm \sqrt{138}}{6}
=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}
Answer:
The width of member is as follows:
b = 3 ft
b = 3 × 12 in.
b= 36 in.
The depth of member is as follows:
d = 8 ft
d = 8 × 12 in.
d=96 in.
Since the structure used is Douglas fir-Larch lumber of size 3 × 8 size. Hence, tensile strength, f =1000 psi
Calculate the net area of the member as follows:
A = (b - ∅) × d
A= (36 - 7/8) × 96
Calculate the maximum axial tensile load by ASD method as follows:
P = f × A
P = 1000 x 3372
P = 3372000 lbs
P = 3372 kips
1500ML=1.5 Liters
Move decimal three places to the left, or divide 1500/1000
1000ML=1L
