In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

${6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20$

3 0

3 years ago

How many non-congruent triangles can be formed by connecting 3 of the vertices of the cube?

alexira [117]

Answer:

The number of non-congruent triangles that can be formed by connecting 3 of the vertices of the cube is 3 non-congruent triangles

Step-by-step explanation:

From the three dimensional shape of a cube, triangles can be constructed from;

1) 6 side faces

2) 4 front face to opposite vertices triangles

3) 4 rear face to opposite vertices triangles

Each face can produce ₄C₃ = 4 triangles

Therefore;

The total number of triangles that can be formed = 4 × 6 + 4 × 4 + 4 × 4 = 56 triangles

Of the 56 triangles, it will be found that all 24 triangles from the different 6 direct faces will have the same dimension of 1, 1, √2 are congruent

The 24 triangles formed by the sides of the faces and an adjacent diagonal have the same dimension of 1, √2, √3 and are congruent

The 8 triangles formed by joining the three diagonals have the same dimension of √2, √2, √2 are congruent

Therefore, the 56 triangles comprises of a combination of three non-congruent triangle.

There are only 3 observed non congruent triangles formed by connecting three of the vertices of the cube.

3 0

3 years ago

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An axiom in euclidean geometry states that in space there are how many points

Rama09 [41]

Infinite amounts of [oints

6 0

3 years ago

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