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SOVA2 [1]
3 years ago
15

Solve h=-16t^2+20t+6?​

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

i think this is the answer Simplifying h(t) = -16t2 + 20t + 6 Multiply h * t ht = -16t2 + 20t + 6 Reorder the terms: ht = 6 + 20t + -16t2 Solving ht = 6 + 20t + -16t2 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Divide each side by 't'. h = 6t-1 + 20 + -16t Simplifying h = 6t-1 + 20 + -16t Reorder the terms: h = 20 + 6t-1 + -16t

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Given csc(A) = 65/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational
andrew11 [14]
<h3>Answer:  65/63</h3>

=================================================

Explanation:

Draw a right triangle in the first quadrant, aka northeast quadrant, as shown in the diagram below.

Cosecant involves the ratio of hypotenuse over opposite. It's the reciprocal of sine

sin(angle) = opposite/hypotenuse

csc(angle) = hypotenuse/opposite

since csc = 1/sin

Use the pythagorean theorem to solve for b in the diagram

a^2+b^2 = c^2

16^2+b^2 = 65^2

256+b^2 = 4225

b^2 = 4225-256

b^2 = 3969

b = sqrt(3969)

b = 63

So this is the adjacent side. The secant ratio involves hypotenuse over adjacent (it's the reciprocal of cosine).

sec(angle) = hypotenuse/adjacent

sec(A) = 65/63

5 0
3 years ago
Find the derivative of sec3t/tan5t
Natali [406]
We will need to use Quotient Rule along with the chain Rule.
Also we need to know the basic derivatives of sec and tan.

\frac{d}{dt} sec(u) = sec(u) tan(u) \frac{du}{dt}
\frac{d}{dt} tan(u) = sec^2 (u) \frac{du}{dt}

We will refer to those later.
Now lets look at the Quotient rule:
(\frac{f}{g})' = \frac{f' g - fg'}{g^2}
f(t) = sec(3t)  ,   g(t) = tan(5t)
Find f'(t) and g'(t) using derivatives from top of post.
Note that u = 3t for f(t)   and u = 5t for g(t).
f'(t) = 3sec(3t) tan(3t)
g'(t) = 5 sec^2 (5t)
Substituting into quotient formula:
\frac{3 sec(3t) tan(3t) tan(5t) - 5 sec(3t) sec^2 (5t)}{tan^2 (5t)} 
4 0
3 years ago
Please help me answer this with the correct answer :)
Vlad1618 [11]

Answer:C

Step-by-step explanation:

For every function; f(x) = y

Each value of 'x' produces only one output 'y'

A,B and D are not functions because this rule is violated. It is observed that on the graphs of A,B and D, there exists a value of x that produces two outputs(y).

Hence, C is the correct option as it produces only one output 'y' for each value of x.

8 0
3 years ago
**13 POINTS; I NEED HELP PLEASE
Lena [83]
The answer should be Census! Census, by goggle meaning “an official count or survey of a population, typically recording various details of individuals.”
Cluster samples are more of different groups being surveyed.
I’m this case it’s for the ride, so it’s only for one thing and No one is getting split up.
5 0
3 years ago
How many solutions does this system have?
SSSSS [86.1K]
This can only have one
4 0
3 years ago
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