Answer:
A rhombus and a square since a square is also a rhombus.
Answer:
![\sqrt[5]{z} = \sqrt[5]{(-2)^{5} } \therefore \sqrt[5]{z} = -2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bz%7D%20%20%3D%20%5Csqrt%5B5%5D%7B%28-2%29%5E%7B5%7D%20%7D%20%20%20%5Ctherefore%20%5Csqrt%5B5%5D%7Bz%7D%20%3D%20-2)
Step-by-step explanation:
i) z = -32
ii)
Divide it into chunks of area you can find. One way to divide it is
.. a rectangle 2 mi x 5 mi at upper left.
.. a rectangle 8 mi x 6 mi down the middle
.. a rectangle 3 mi x 4 mi at lower right
.. a triangle 5 mi x 6 mi at lower left
Then the sum of areas is
.. (2 mi)*(5 mi) +(8 mi)*(6 mi) +(3 mi)*(4 mi) + (1/2)*(5 mi)*(6 mi)
.. = 10 mi^2 +48 mi^2 +12 mi^2 +15 mi^2
.. = 85 mi^2
Answer:
Multiply then add them and them that's your answer.
Step-by-step explanation:
None of the above because it will be 3.2 or -3.2
