Arrange the steps in the correct order to solve this trigonometric equation 2sin^2 x -sinx -1 =0 for 0 degrees is less than or e
qual to x is less than or equal to 90 degrees
1 answer:
Answer:
<h3>90°</h3>
Step-by-step explanation:
Given the trigonometry equation;

Step 1; Let p = sin(x) to have;

Step 2: factorize the resulting quadratic equation:

Step 3: Find x:
when p = 1
sin(x) = 1

also when p -1/2
sin (x) = -1/2


Since 150° is not within the range 0<x<90, then the only solution is 90°
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hope this helps!!