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3 years ago

Write the numbers in order from greatest to least. 7.982, 7.981, 8.782, 8.981

Mathematics

1 answer:

ziro4ka [17]3 years ago

7 0

Answer:

Step-by-step explanation:

To order decimals is to subtract, line up, and comparing digits.

Comparing digits is a good way to order decimals for greatest to least.

(Most Understood.)

<h3>Comparing Decimals:</h3><h3 />

We could put numbers in any order to compare digits, but you should look closely:

Numbers can<u> Trick You.</u>
<u>Be wise, look closely.</u>
<u>If the digit is 0 for a number, the other number is greater if it's not 0.</u>

Lastly, <u>you (cannot) multiply, divide, add, or subtract.</u>

__________________________________________

First, we pick 2 numbers to compare, maybe 8.782 and 8.981.

We look at the digits for both numbers.

We see 8's, And 7 and 9, 9 is greater, so 8.<u>9</u>81 is the greatest and 8.<u>7</u>82 is the 2nd greatest.

<h3>8.981, 8.782, ?.???, ?.??? Is Our Order so far.</h3>

Our last 2 numbers are 7.981 and 7.982,

We look at the digits for both numbers.

We see 7's, we see 9's, and we see 8's, but 1 and 2. 2 is greater so 7.98<u>2</u> is the 3rd greatest and 7.98<u>1</u> is the least.

<h3>Our order is: 8.981, 8.782, 7.982, 7.981.</h3><h3>We checked it by comparing wisely. (√ Means Check)</h3>

Best of Luck to you.

If you have any questions, feel free to comment below.

-Also if anything is confusing!!

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8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.