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3 years ago

Find the volume of the rectangular prism. IN in. 4 in. 9-in. 2 I

Mathematics

1 answer:

prisoha [69]3 years ago

6 0

Answer:

V = 36 in³

Step-by-step explanation:

The volume of a rectangular prism is given by the formula V = l × w × h

Here our length is $9\frac{1}{2}$ , our width is 4, and our height is $4\frac{1}{2}$

Plugging in these values to our formula give us $V=(9\frac{1}{2})(4)(4\frac{1}{2})= 36$

V = 36 in³

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The standard form of the equation of a parabola is y= 1/2 x^2 - 4x + 21 what is the vertex form of the equation?

denis-greek [22]

the vertex of the equation is (4,13)

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3 years ago

The graph of a line has a slope of 3 and passes through the point (–4, –5). What is the equation of the line in point-slope form

Contact [7]

Y + 5 = 3(x + 4)
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So y - -5 = 3 (x - -4)

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3 years ago

Select the correct answer.

zvonat [6]

Answer:

Step-by-step explanation:

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3 years ago

Math To Do, i-Ready

marysya [2.9K]

Answer:

The price before tip ,Mrs. Henry's move is 351.9 $

Step-by-step explanation:

Given:

Total bills of 414 $ in which 15 % is tip

To Find:

What is the price before tip, Mrs. Henry's move

Solution:

Total bill amount is 414$

And 15 % is tip bill and 85 % is bill before tip

So,

85 % of total bill can give price before tip

calculate 15 % and subtract from total bill.

So 85 % of 414=0.85 *414

=351.9 $

15 % 414=0.15 *414

=62.1 $

Price before Tip is =414$ -62.1 $

=351.9$

So BY Both ways we can get same answer i.e. 351.9 $

8 0

3 years ago

Read 2 more answers

The center of a hyperbola is located at the origin. One focus is located at (0, 20), and its associated directrix is represented

bearhunter [10]

Answer:

The equation of the hyperbola is $\frac{y^2}{256}-\frac{x^2}{144} =1$ .

Step-by-step explanation:

Since directrix is $y=\frac{-256}{20}$ , therefore the hyperbola is along the y-axis.

Focus of the hyperbola are (0,c) and (0,-c).

The given focus is (0,20), therefore the value of c is 20.

Directrix of the hyperbola is

$y=\pm \frac{a^2}{c}$

$\frac{-256}{20}=\pm \frac{a^2}{20}$

$256=a^2$

$a=16$

Therefore the value of a is 16.

The relation between a, b and c is

$a^2+b^2=c^2$

$b^2+(16)^2=(20)^2$

$b^2+256=400$

$b^2=400-256$

$b^2=144$

$b=12$

Therefore the value of b is 12.

The standard form of the hyperbola is,

$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

Since the value of a is 16 and the value of b is 12, therefore

$\frac{y^2}{256}-\frac{x^2}{144} =1$

6 0

3 years ago

Read 2 more answers