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irga5000 [103]
2 years ago
12

The pool holds 15069 of water and is leaking at a rate of 4 gallons per day how many gallons will remain in the pool after 141 d

ays
Mathematics
1 answer:
Veronika [31]2 years ago
8 0

Answer:

Water remaining in the pool after 141 days = 14,505 gallons

Step-by-step explanation:

Total number of gallons of water in the pool = 15,069

Rate of leakage of water = 4 gallons per day

Using unitary method

1 day leakage of water from the pool = 4 gallons

∴ In 141 days leakage of water from the pool will be = 141\times4=564 gallons

After leaking 564 gallons of water, total gallons of water that will remain in the pool will be = 15,069-564=14,505 gallons

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nataly862011 [7]
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In parallelogram DEFG if m_DEF=110° find m_FGD.<br> E<br> 110°<br> D<br> G
Sergio039 [100]

Answer:

E=x

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3 0
3 years ago
Please explain, thank you
RoseWind [281]

Answer:

C. 2.

Step-by-step explanation:

The graph descends from the left  so the coefficient of the leading term is negative. It is also a cubic equation with zeros of -20, about 6.5 and about 13. so we can write the equation as below.  The last 2 values can only be guessed because the x axis only shows values which are multiples of 5.

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(This is only an approximation).

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f(-10) = -20 so we have

-20 = a (-10 + 20)(-10-6.5)(-10 - 13)

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a = -20 / (10)(-16.5)(-23)

a = -0.0053

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= 1.7 approximately.

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2 years ago
3. You have 3 consecutive numbers, with the smallest number n.
mr Goodwill [35]
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