Answer
13
Step-by-step explanation:
Answer:
The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.
Step-by-step explanation:
The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.
For example, if we consider a quadratic equation x² + 6x + 1 = 0, then two of its roots are - 3 + √8 and - 3 - √8 and they are conjugate of each other. (Answer)
The answer is 3, since 3*3*3 equals 27
We have been given a graph of piecewise function. Using that we have to select the function from given choices which is represented by graph.
g(x) = −2x, −2 < x < 0
Answer:
NO. Because g(x) = −2x has negtive slope so that means it goes downward also there is no y-intercept in g(x) = −2x but the only graph that has y-intercept in given graph goes upwawrd so that can't be answer.
g(x) = −2, x < −2
Answer:
YES. Because g(x) = −2 is a horizontal line which is only on the left side oof x=-2. Graph of this part is present in given graph. So yes it is answer.
g(x) = x − 2, −2 < x < 1
Answer:
NO. Because g(x) = x−2 has y-intercept at y=-2 and slope 1 so that means graph of g(x)= x-2 must be going upward and crossing at y=-2 butt there is no such graph. Hence this can't be answer.
g(x) = −2x + 6, x ≥ 1
Answer:
YES. Because g(x) = −2x+6 satisfies the graph which is going downward.
g(x) = x/2+ 1, –2 ≤ x < 1
Answer:
YES. Because g(x) = x/2+ 1 satisfies the graph which is going downward.
