The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...
<u><em>Explanation</em></u>
Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2
The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners 
For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.
So, the possible ways for selecting 2 pasta dinners 
The possible ways for selecting 3 pasta dinners 
The possible ways for selecting 4 pasta dinners 
The possible ways for selecting 5 pasta dinners 
Thus, the probability for selecting at least 2 pasta dinners 
2/5, five different areas and two are black
There is no way I can answer this without the graph
Answer: see below
<u>Step-by-step explanation:</u>
I'm not sure exactly what you are asking for but here is what the box plot tells you:
Minimum is 17 items.
Q1 (Lower Quartile) is 22 items. So, 25% of the customers bought 22 items.
Q2 (Median) is 32 items. So, 50% of the customers bought 32 items.
Q3 (Upper Quartile) is 35 items, So, 75% of the customers bought 35 items.
Maximum is 62 items.
The data is "heavier" on the right so it is skewed left.
Range is 62 - 17 = 45
IQR (Interquartile range) is Q3 - Q1 = 35 - 22 = 13