An atom can have 2.5 protons, as long as it also has 2.5<br> electrons.<br> TRUE. Or <br> FALSE

Which of the following are likely to form a covalent bond?

harkovskaia [24]

Answer:

• Hydrogen and oxygen atoms

Explanation:

Hydrogen and oxygen are nonmetals. They are most likely to share electrons and form a covalent bond.

A is wrong. Gold is a metal, so it will form metallic bonds.

O is wrong. Neon is a noble gas. It has a complete octet, so it is unlikely to form covalent bonds.

D is wrong. Mg is a metal, and Br is a nonmetal. They are more likely to form ionic bonds.

6 0

3 years ago

N which direction will the net reaction proceed.

finlep [7]

Answer:

1) The correct answer is option b.

2) The correct answer is option a.

Explanation:

1)

$X+Y\rightleftharpoons Z$

At 300 K, the value of the $K_p=1.00$

The $K_c$ and $K_p$ is related by :

$K_p=K_c\times (RT)^{\Delta n}$

where,

$K_p$ = equilibrium constant at constant pressure

$K_c$ = equilibrium concentration constant

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 300 K

$\Delta n$ = change in the number of moles of gas = 1 - 2 = -1

Now put all the given values in the above relation, we get:

$1.00=K_c\times (0.0821 L atm/(K mol)\times 300)^{-1}$

$K_c=24.63$

The $K_c$ of the reaction = 24.63

Given = [X] = [Y] = [Z] = 1.0 M

Value of reaction quotient = Q

$Q=\frac{[Z]}{[X][Y]}=\frac{1.0 M}{1.0M\times 1.0 M}=1$

$Q$ , the equilibrium will move in forward direction that is in the right direction.

2)

$X+Y\rightleftharpoons Z$

At 300 K, the value of the $K_p=1.00$

Given = $P_x = P_z = 1.0 atm, P_y = 0.50 atm$

Value of reaction quotient in terms of partial pressure = $Q_p$

$Q_p=\frac{P_z}{P_x\times P_y}=\frac{1.0 atm}{1.0 atm\times 0.50 atm}$

$Q_p=2$

$Q_p>K_p$ the equilibrium will move in backword direction that is in the left direction.

6 0

3 years ago

Dinitrogen tetraoxide is a colorless gas at room temperature. It can dissociate into nitrogen dioxide, which is a reddish brown

Alenkinab [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The calculation and filling of the table based on the ratio indicated by the column is shown on the second uploaded image

1 This is True

2 This is False

3 This is False

4 This is True

5 This is True

Explanation:

Based on your calculations, indicate whether each statement is True (T) or False (F):

Considering the first statement

Looking at the question we can see that the first statement is TRUE this because all the three experiment have different initial concentration (3.5,3.0 & 2.6)

Considering the second statement

Looking at table we can see that the second statement is FALSE because

the ratio value of [NO2]/ [N2O4] in all three experiment have different value 1.4 , 1.5 & 1.7 is not a constant value.

Considering the Third statement

Looking at the table we can see that the third statement is FALSE this is because the ratio value of 2[NO2]/ [N2O4] in all three experiment have different value 2.7, 3.0 & 3.3 is not a constant value.

Considering the Fourth statement

Looking at table we can see that the fourth statement is TRUE this is because the ratio value of $[NO2]^{2}/ [N2O4]$ in all three experiment have same value 3.9, 3.9 & 3.9 is a constant value.

Considering the Fifth statement

Looking at table we can see that the fifth statement is TRUE this is because

each having different set of Equilibrium concentration

3 0

4 years ago

The element iodine would be expected to form covalent bond(s) in order to obey the octet rule. Use the octet rule to predict the

zhannawk [14.2K]

Answer:

HI (hydrogen iodide).

Explanation:

Hello,

In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:

$H-I$