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storchak [24]
3 years ago
11

How many moles are in 12 grams of NH3?​

Chemistry
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

molecular weight of NH3 or grams This compound is also known as Ammonia. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles NH3, or 17.03052 grams.

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Which of the following is not true about sedimentary rocks?
Klio2033 [76]
Answer:  [D]:  "They are not part of the rock cycle."  .
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6 0
4 years ago
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Which has more mass, a mole of water (h2o) or a mole of glucose (c6h12o6)?
Semenov [28]
It is important to note that mass and mole pertain to different units of measurement, thus, 1 mole of one substance may have a lower or higher mass compared to a different substance. The mass of an object gives a measure of the number of atoms present in the substance while the number of moles of a substance refers to the amount of a chemical substance it has and is often used for chemical reactions. 

For this problem, we first get the molar mass of each substance:

Molar mass of H2O = 18.0153 g/mol
Molar mass of C6H12O6 = 180.1559 g/mol

We then convert each substance into units of mass (grams), where:

1 mol H20 x 18.0153 g/mol = 18.0153 g H20
1 mol C6H12O6 x 180.1559 g/mol = 180.1559 g C6H12O6

It was then determined that 1 mole of glucose has more mass than 1 mole of water. 
3 0
4 years ago
How many moles of gas X are present if the gas has a volume of 2dm³ at room temperature and pressure? Give your answer to 2 deci
bezimeni [28]

Answer:

Approximately 0.08\; \rm mol, assuming that this gas is an ideal gas.

Explanation:

Look up the standard room temperature and pressure:25\; \rm ^{\circ}C and P = 101.325 \; \rm kPa.

The question states that the volume of this gas is V = 2\; \rm dm^{3}.

Convert the unit of all three measures to standard units:

\begin{aligned} T &= 25\; \rm ^{\circ}C \\ &= (25 + 273.15)\; \rm K \\ &= 293.15\; \rm K\end{aligned}.

\begin{aligned}P &= 101.325\; \rm kPa \\ &= 101.325 \; \rm kPa \times \frac{10^{3}\; \rm Pa}{1\; \rm kPa} \\ &= 1.01325 \times 10^{5}\; \rm Pa\end{aligned}.

\begin{aligned}V &= 2\; \rm dm^{3} \\ &= 2 \; \rm dm^{3} \times \frac{1\; \rm m^{3}}{10^{3}\; \rm dm^{3}} \\ &= 2 \times 10^{-3}\; \rm m^{3}\end{aligned}.

Look up the ideal gas constant in the corresponding units: R \approx 8.31\; \rm m^{3}\cdot Pa \cdot mol^{-1} \cdot K^{-1}.

Let n denote the number of moles of this gas in that V = 2\; \rm dm^{3}. By the ideal gas law, if this gas is an ideal gas, then the following equation would hold:

P \cdot V = n \cdot R \cdot T.

Rearrange this equation and solve for n:

\begin{aligned}n &= \frac{P \cdot V}{R \cdot T} \\ &\approx \frac{1.01325 \times 10^{5}\; {\rm Pa} \times 2 \times 10^{-3}\; {\rm m^{3}}}{8.31 \; {\rm m^{3} \cdot Pa \cdot mol^{-1} \cdot K^{-1}} \times 293.15\; {\rm K}} \\ &\approx 0.08\; \rm mol\end{aligned}.

In other words, there is approximately 2\; \rm mol of this gas in that V = 2\; \rm dm^{3}.

6 0
3 years ago
How could you use melting and boiling point to identify a substance
ivanzaharov [21]

Answer:

At low temperatures than melting point the substance remain as a solid. Then from melting point temperature to boiling point the substance will remain as a liquid. This is the temperature at which a liquid become a gas. When we increase the temperature of a liquid it will become gas at its boiling point.

Explanation:

3 0
3 years ago
What would you expect from an endothermic reaction?
Zanzabum
D. The products will have more energy than the reactants.

6 0
3 years ago
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