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Monica [59]
3 years ago
7

The blank is the energy difference between reactants and products in a chemical reaction

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

breUG6KGHU

Explanation:

GHVFHMJHGUVILYU

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The process of adding hydrogen to the double bonds in unsaturated fatty acids to extend the shelf-life of food products is calle
Viktor [21]

Hydrogenation is a process that involves adding hydrogen to the double bonds in unsaturated fatty acids to extend the shelf-life of food products.

<h3>What is hydrogenation?</h3>

Hydrogenation can be defined as a chemical process that involves an addition of hydrogen to the double bonds in unsaturated fatty acids to extend the shelf-life of food products.

<h3>The purpose of hydrogenation.</h3>

In Science, some of the purpose of hydrogenation include the following:

  • Conversion of liquid oil into solid fat.
  • To alter a fat's consistency level.
  • To stabilize a fat or an oil.

Read more on unsaturated fatty acids here: brainly.com/question/1580524

8 0
2 years ago
Keratinocytes begin to die in the stratum granulosum. Keratinocytes begin to die in the stratum granulosum. True False
Scrat [10]

Answer:

FALSE

Explanation:

Keratinocytes begin to die in the stratum granulosum is False.

6 0
3 years ago
How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.
Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

8 0
3 years ago
A satellite can move around Earth in a circular orbit at constant height because
dybincka [34]
I believe it’s answer B because even in space gravity plays roles.
4 0
3 years ago
What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

7 0
3 years ago
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