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assuming the magnesium ribbon wasn't sufficiently polished to remove a coating of magnesium oxie on the surface. how would this

Ira Lisetskai [31]

The magnesium ribbon wasn't sufficiently polished to remove a coating of magnesium oxie on the surface. how would this affect the volume of hydrogen gas produced? would this error cause the gas constant to be overestimated, underestimated, or remain unaffected?

1. Since, the magnesium ribbon wasn’t sufficiently polished to remove a coating of magnesium oxide on surface, the actual mass of magnesium taken will be less (as it also contains magnesium oxide). Hence, the number of moles of magnesium reacted and the number of moles of hydrogen produced will be less. Due to this, the volume of hydrogen gas produced will be less and the gas constant will be underestimated. R=\frac {PV}{nT} . Here n is calculated from weight of Mg taken but V is measured. Thus values of n will be same but the value of V will be lower. Hence, the value of R will be lower.

2. When droplets of water are remaining in the eudiometer tube, there volume will be added to the volume of hydrogen and the measured volume of hydrogen will be more than actual volume. Due to this, the value of the gas constant will be overestimated.

3. When small amount of hydrogen dissolves in water, the measured volume of hydrogen will be lower than the actual volume. This will underestimate the value of the gas constant.

4. When the temperature of the gas was underestimated, the value of the gas constant will be overestimated as the gas constant is inversely proportional to the temperature. {PV}

R=

{nT}.

Magnesium is a chemical detail with the symbol Mg and atomic number 12. it is a glittery gray solid which stocks many bodily and chemical residences with the alternative 5 alkaline earth metals (institution 2 of the periodic desk).

This element is produced in huge, growing old stars from the sequential addition of three helium nuclei to a carbon nucleus. whilst such stars explode as supernovas, a lot of the magnesium is expelled into the interstellar medium wherein it may recycle into new big name structures. Magnesium is the eighth maximum abundant element inside the Earth's crust and the fourth maximum not unusual detail in the Earth (after iron, oxygen and silicon), making up 13% of the planet's mass and a big fraction of the planet's mantle. it's miles the 0.33 maximum abundant detail dissolved in seawater, after sodium and chlorine.

Learn more about Magnesium here:-brainly.com/question/25860912

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8 0

2 years ago

In the lab you react 2.0 g of Na2CO3 with enough CaCl2. According to the reaction Na2CO3 + CaCl2 -> CaCO3 + 2NaCl How much Ca

vlada-n [284]

Answer:

1.89 g CaCO₃

Explanation:

You will have to use stoichiometry for this question. First, look at the chemical equation.

Na₂CO₃ + CaCl₂ ==> 2 NaCl + CaCO₃

From the above equation, you can see that for one mole of Na₂CO₃, you will produce one mole of CaCO₃. This means that however many moles of Na₂CO₃ you have in the beginning, you will have the same amount of moles of CaCO₃, theoretically speaking.

So, convert grams to moles. You should get 0.0189 mol Na₂CO₃. This means that you will get 0.0189 mol CaCO₃. I'm not sure what units you want the answer in, but I'm going to give it in grams. Convert moles to grams. Your answer should be 1.89 g.

3 0

4 years ago

A flexible container at an initial volume of 8.15 l contains 6.51 mol of gas. more gas is then added to the container until it r

kirill [66]

A flexible container at an initial volume of 7.14 L contains 7.51 mol of gas. More gas isthen added to the container until it reaches a final volume of 17.7 L. Assuming the pressure andtemperature of the gas remain constant, calculate the number of moles of gas added to the container.

3 0

3 years ago

How are science and technology related

KatRina [158]

There is no answer, science is about empirical knowledge, technology is the sum of techniques, skills, methods, and processes. I do not believe that you will find a answer for that.

7 0

3 years ago

Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol2870 kJ/mol ( Δ????°

MaRussiya [10]

Answer:

Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17

Explanation:

Energy released during the complete combustion of 1 mole glucose = 2870 kJ

Energy required/muscle contraction cycle = 67 kJ/contraction

Energy conversion efficiency = 39%

Actual amount of energy converted to contraction per mole of glucose is:

$=\frac{39}{100} *2870 kJ=1119.3 kJ$

Total contraction cycles fueled by the above energy is:

$=\frac{1119.3\ kJ}{67\ kJ/contraction} =16.7\ i.e.\ around\ 17\ contractions$

5 0

3 years ago