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AlladinOne [14]
3 years ago
13

The volume vv of a pyramid is given by the formula v=13bhv=13bh, where bb is the area of the base and hh is the height.

Mathematics
1 answer:
Setler [38]3 years ago
4 0

Volume of pyramid(V) = \frac{1}{3}bh

where 'b' is the base area and 'h' is the height.

We have to determine the formula for height 'h'.

V = \frac{1}{3}bh

Multiplying by '3' on both the sides of the equation.

3V = bh

h = \frac{3V}{b}

So, the formula for height 'h' of pyramid is h = \frac{3V}{b}.

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The Coopers own two vehicles, a mini-van and sedan. The following functions represent the resale value of both cars, in thousand
velikii [3]

Answer:

h(x) = 57(0.8)^x

Step-by-step explanation:

Given

f(x) = 32(0.8)^x

g(x) = 25(0.8)^x

Required

A function that represents the total resale value of the two vehicles

To do this, we simply add up the functions

h(x) = f(x) + g(x)

h(x) = 32(0.8)^x + 25(0.8)^x

Factorize

h(x) = (32 + 25)(0.8)^x

h(x) = 57(0.8)^x

6 0
3 years ago
Bubbles bakery has 24 oatmeal cookies, 36 vanilla bean cookies, 42 chocolate chip cookies. What is the greatest common factor bu
STatiana [176]

Answer:6

Step-by-step explanation:

We have three groups of cookies as follows:

24   oatmeal

36   vanilla bean

42  chocolate chip

If we breack down into factors we get

24    2       24 = 2³ * 3        36    2   36 = 2²*3³         42   2   42 = 2*3*7

12     2                                 18    2                              21   3

6      2                                   9    3                                7   7

3      3                                   3    3                                1

1                                             1

Fom where we can get that biggest common factor is 6

24 ÷  6      =  4

36 ÷  6      =  6

42 ÷  6      =  7

Then Bakery will have  4 groups of oatmeal cookies, 6 of vanilla bean, and 7 chocolate chip

7 0
3 years ago
Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x

We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

for 0\le x\le\frac3{\sqrt2} and 0\le y\le3. Then the flux of \vec F, assumed to be

\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

3 0
3 years ago
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
3 years ago
.....................................
nirvana33 [79]

Answer:

Is this a question or..........

Step-by-step explanation:

5 0
3 years ago
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