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erastovalidia [21]
3 years ago
14

Austin consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Austin's bod

y decreases exponentially. The 10-hour decay factor for the number of mg of caffeine in Austin's body is 0.2785.
a. What is the 5-hour growth/decay factor for the number of mg of caffeine in Zach's body?
b. What is the 1-hour growth/decay factor for the number of mg of caffeine in Zach's body?
Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

  • 5-hour: 0.5277
  • 1-hour: 0.8800

Step-by-step explanation:

The decay factor for time t can be written as ...

  0.2785^(t/10)

Then the 5-hour decay factor is ...

  0.2785^(5/10) ≈ 0.5277

and the 1-hour decay factor is ...

  0.2785^(1/10) ≈ 0.8800

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James and Sarah went out to lunch the price of a lunch for both of them was $20 they tipped their server 20% of that amount. How
Oxana [17]

Answer:

$24

Step-by-step explanation:

James and Sarah's lunches cost $20 each, so the total price of their meal is 20 * 2 = $40.

They tipped their server 20% of $40, so to find 20% of 40 you would multiply:

40 * 0.20 = 8

Add 8 to 40 = $48.

If they shared this lunch price of $48 equally then they each paid half of this price.

48 / 2 = 24

They each paid $24.

8 0
3 years ago
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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.
Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

with partial derivatives (set to 0)

L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
L_z=5xy+2\lambda z=0
L_\lambda=x^2+y^2+z^2-1=0

We then observe that

xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2

So, ignoring the critical point we've already found at (0, 0, 0),


5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
5 0
3 years ago
Suppose David had $65 to spend on his ticket and some shirts. He already used $32.25 on his ticket and the shirts are $14.50. Ho
DiKsa [7]
We know $65 were spent on his ticket and some shirts.Which he used 32.25 which leaves us  with 27.75 and a shirt cost 14 and 50 cent .

SO you need to divide 27.75 in 14 and 50 cents which is equal to
   
             14 plus 14 equals 28
              75 plus 50 equals 1 and 25 cents

David can buy two shirts 

Hope this helped


5 0
3 years ago
Identify the values that should be written to complete the X diagram.
cestrela7 [59]

Answer:

See the attachment for what goes on your X diagram.

Rewrite: x² -7x +4x -28

Grouping: (x² -7x) +(4x -28) = x(x -7) +4(x -7) = (x +4)(x -7)

Step-by-step explanation:

The given quadratic is ...

... x² -3x -28 . . . . . a=1, b=-3, c=-28

a) The value at the top of the X diagram is the product a·c = 1·(-28) = -28.

The value at the bottom of the X diagram is the coefficient b = -3.

The values on the sides of the diagram are the factors of -28 that add up to make -3. These are -7 and 4. That is, ...

(-7)·(4) = -28

(-7)+(4) = -3

b) Since the two values on the sides of the diagram add up to give "b", the value of "b" in the equation can be rewritten as the sum of these two numbers. Doing that, we have ...

... x² -3x -28

... = x² +(-7+4)x -28

... = x² -7x +4x -28 . . . . . . order does not matter. It could also be x² +4x -7x -28

c) We can group pairs of terms in the rewritten expression and factor each pair.

... = (x² -7x) +(4x -28) . . . . . first pair has a common factor of x; second pair, 4

... = x(x -7) +4(x -7) . . . . . . . these terms now have a common factor: (x -7)

... = (x +4)(x -7) . . . . . . . . . . the complete factorization of x² -3x -28

3 0
3 years ago
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