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11 months ago

5

Which angle is an adjacent interior angle to ∠jkm? ∠jkl ∠mkl ∠klm ∠lmk

1 answer:

Semmy [17]11 months ago

8 0

∠mkj angle is an adjacent interior angle to ∠jkm

Adjacent interior angles are two angles that share a common vertex and a common side. In the given angle ∠jkm, the common vertex is at point "k" and the common side is the line segment joining points "j" and "m". Therefore, the adjacent interior angle to ∠jkm is ∠mkj.

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Orlov [11]

Answer:

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(4,-1). Parallel to y=-4x+2

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2 years ago

What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.

schepotkina [342]

Answer:

2

Step-by-step explanation:

The given equation of line is

$3x+6y=-18$

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

$3x+6y+18=0$ ...(i)

If a line is defined as $ax+bx+c=0$ , then the slope of the line is

$m=-\dfrac{a}{b}$

In equation (i), a=3, b=6 and c=18. So, slope of the line is

$m_1=-\dfrac{3}{6}=-\dfrac{1}{2}$

Let $m_2$ be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

$m_1\cdot m_2=-1$

$(-\dfrac{1}{2})\cdot m_2=-1$

Multiply both sides by -2.

$m_2=2$

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6 0

3 years ago

Can any one help please :)

Gemiola [76]

Answer:

B

Step-by-step explanation:

First, subtract 3 by the numbers

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Remember to flip the inequality signs

Second, divide all the numbers by 4

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Flip the inequality signs again

-2 > x > 1

I am not very experienced with these problems so I might be wrong.

7 0

2 years ago

Read 2 more answers