The quantity of each type of seats sold are as follows:
- Movie and a dinner seat = 200
According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.
That is, x = 4y
Also, total seats
= (x) + (y) + (z) = 3000...….............eqn(1)
Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.
- 20x + 35y + 15z = 53000...........eqn(2)
By substituting 4y for x in equations 1 and 2; we have;
<em>5y + z = 3000</em>..…........eqn(3) and
<em>115y + 15z = 53000</em>.........eqn(4)
By solving equations 3 and 4 simultaneously; we have;
y = 200 and z = 2000
and since x = 4y
x = 800
The quantity of each type of seats sold is as follows:
- Movie and a dinner seat = 200
Read more:
brainly.com/question/12413726
Answer:
12
Step-by-step explanation:
Let's put the equations in standard form. For the first equation, we have:
−11y=6(z+1)-13y
2y−6z=6
y−3z=3
The second equation is:
4y−24=c(z−1)
4y−cz=24−c
If we multiply the first equation by 4, we get:
4y-12z=12
Comparing the two equations, we see that if c=12, both equations will be the same and there will be infinitely many solutions.
The correct value of c is 12.
A. from 67.86 all the way to the end. (67.86 is not filled)
b. $67.86,
$80.00,
$70.00(values equal to or greater than $67.86.)
c. There are many values that represent this inequality.(values equal to or greater than $67.86)
Hope this helped☺☺
