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2 years ago

What is the difference between the reciprocal of a trig function and the inverse of a trig function?

1 answer:

5 0

Inverse is used to find the value of an angle. The inverse of a trigonometric function gives you the angle instead of the ratio. Commonly, these are denoted with the prefix "arc-". So, the inverse of the tan function is the arctan function.

The reciprocal of a trigonometric function is simply its algebraic reciprocal--that is, 1 over the function.

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Solve for A if F=MA and F=10 and M=2.5

gogolik [260]

Answer:

$\boxed{\sf A = 4}$

Given:

F = MA

F = 10

M = 2.5

To Find:

Value of A

Step-by-step explanation:

$\sf Substituting \ values \ of \ F \ and \ M \ in \ F = MA:$

$\sf \implies 10 = 2.5A$

$\sf \implies 2.5A = 10$

$\sf Dividing \ both \ side \ of \ 2.5A = 10 \ by \ 2.5:$

$\sf \implies \frac{2.5}{2.5} A = \frac{10}{2.5}$

$\sf \frac{2.5}{2.5} = 1 :$

$\sf \implies A = \frac{10}{2.5}$

$\sf \frac{4 \times \cancel{2.5}}{ \cancel{2.5}} = 4 :$

$\sf \implies A = 4$

3 0

4 years ago

Read 2 more answers

Which of the following statements are not true in developing a confidence interval for the population mean?

frutty [35]

Answer:

b) The width of the confidence interval becomes narrower when the sample mean increases.

Step-by-step explanation:

The confidence interval can be calculated as:

$\bar{x} \pm \text{Test Statistic}\displaystyle\frac{\sigma}{\sqrt{n}}$

a) The width of the confidence interval becomes wider as the confidence level increases.

The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.

b) The width of the confidence interval becomes narrower when the sample mean increases.

The above statement is false. As the sample mean increases the width of the confidence interval increases.

c) The width of the confidence interval becomes narrower when the sample size n increases.

The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.

8 0

3 years ago

An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below

madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that $\mu = 79.7, \sigma = 8.4$