The greatest common factor of 72 and 4 is 4.
Set 7x-4 and 31 equal to each other
7X-4=31
Add four to both sides
7X=27
X=3
The answer is D
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So



has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
Answer:
9 at minimum
Step-by-step explanation:
a minimum of 9 because it takes a total of 8 rides to take back a full 18 cars back and the 9th ride takes back the remainder which is 0.27777777778 times 18 cars
Answer:
f(y) = 4y2 - 4v
f(y) = 4y² - 4(-4) = 4y² + 16
f(y) = 4y² - 4(-3) = 4y² + 12
f(y) = 4y² - 4(-2) =4y² + 8
f(y) = 4y² - 4(-1) = 4y² + 4
Step-by-step explanation: