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Elena L [17]
3 years ago
13

PLEASE HELP ME WITH THIS QUESTION

Mathematics
2 answers:
valentina_108 [34]3 years ago
4 0
Set 7x-4 and 31 equal to each other
7X-4=31
Add four to both sides
7X=27
X=3
The answer is D
GREYUIT [131]3 years ago
3 0

As per the problem we can see that

There two triangles with equal corresponding sides.

So we can set up the equation as below:

7x-4=31\\ \\ \text{Add 4 on both the sides we get}\\ \\ 7x-4+4=31+4\\ \\ 7x=35\\ \\ \text{Divide both the sides by 7  we get}\\ \\ x=5\\

Hence the value of x is 5.

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PART A:

The given quadratic equation is 2x²-10x-8=0

The radicand is given by b²-4ac where a, b, and c are the constants in a quadratic form ax²+bx+c

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Radicand b²-4ac = (-10)² - 4(2)(-8) = 100 + 64 = 164

The radicand is >0 hence the quadratic equation has two distinct roots

PART B:

4x²-12x+5 = 0

We can use the factorization method to solve the equation
Firstly, we multiply 4 by 5 to get 20
Then we find the pair of numbers that multiply gives 20 and sum gives -12

The pair of number is -2 and -10
Rewriting the equation 
4x²-2x-10x+5 = 0
2x(2x-1)-5(2x-1) = 0
(2x-1)(2x-5) = 0

2x-1 = 0 and 2x-5 = 0
x = 1/2 and x = 5/2
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