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lianna [129]
3 years ago
12

At a movie theater, 360 people can see a particular movie over a period of 3 hours. At this

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:233

Step-by-step explanation:cause i said so

Aleksandr-060686 [28]3 years ago
3 0

Answer:

1,440 i just multiplied 360 times 4 and got the answer because 360 in 3 hours 3 x 4 = 12

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Marty divided an 8-pound bag of potatoes into a 7 equal piles.Which rational number represents the weight of the potatoes in eac
erma4kov [3.2K]
I think the answer is 1.14 but I'm not sure.
4 0
3 years ago
Solve- -4 1/4+ (5 1/2) =
Mademuasel [1]

Answer:

1,5

Step-by-step explanation:

-4• 1/4 + (5•1/2)=

-4/4 + (5/2)

-1+2,5=

+1,5

3 0
3 years ago
Read 2 more answers
A bag of flour weighed 2.25 kilograms 0.725 kilograms are used in a recipe how many kilograms of flour are left
Mrac [35]
Hello!

You subtract the amount of flour you started with by the amount you used

2.250 - 0.725 = 1.525

The answer is 1.525 kilograms

Hope this helps!
8 0
3 years ago
Read 2 more answers
Solve for e. 9e^2f=49<br> e=±√7f/3<br> e=±7√f/3<br> e=±7√f/3f<br> e=±√7f/3f
Vesnalui [34]
Divide by the coefficient of e^2, then take the square root.
  e^2 = 49/(9f)
  e = ±7/(3√f) = ±(7√f)/(3f)

The 3rd selection is appropriate:
  e=±(7√f)/(3f)


______
When written in plain text (not typeset), any denominator containing arithmetic must be enclosed in parentheses. When the expression is typeset, the surd and the division bar do the grouping for you.
  e=\pm \dfrac{7\sqrt{f}}{3f}
7 0
3 years ago
Read 2 more answers
The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
CaHeK987 [17]

Answer:

The answer is "domain and range are different".

Step-by-step explanation:

Given:

f(x) = \sqrt{\frac{x+1}{x-1}}\\\\g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\

Solve f(x) to find domain and range:

for element x: R:

⇒ x \leq -1 \ \ \ and \  \ \  x > 1 range:

for  \ \ f(x) \times element : 0 \leq f(x)< 1 \ \ \ or \ \ f(x)>1

g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\

Solve for domain:

⇒ \ when \ x \ element \ R: \ \ \ x>1  

Solve for range:  

⇒ g(x) \times element  R : g(x)>1

So, the value of the method f(x) and g(x) (range and domain) were different.  

5 0
3 years ago
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