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alexira [117]
3 years ago
6

Which is the graph of the sequence defined by the function f(x + 1) = Three-fifthsf(x) when the first term in the sequence is 37

5?
On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

On a coordinate plane, 4 points are plotted. The points are (0, 375), (1, 225), (2, 135), (3, 81).

On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 75), (3, 15), (4, 3).

On a coordinate plane, 4 points are plotted. The points are (0, 375), (1, 75), (2, 15), (3, 3).
Mathematics
2 answers:
nadezda [96]3 years ago
9 0

Answer: On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

Step-by-step explanation:

We have the relation:

f(x + 1) = (3/5)*f(x)

such that the first term is 375

Then:

f(1) = 375.

Using the above relation, we have that:

f(1 + 1) = f(2) = (3/5)*f(1) = (3/5)*375 = 225

Then we have the pair (2, 225)

The next term is:

f(2 + 1) = f(3) = (3/5)*f(2) = (3/5)*225 = 135

Then we have the pair (3, 135)

the next term is:

f(3 + 1) = f(4) = (3/5)*f(3) = (3/5)*135 = 81

Then we have the pair (3, 81)

Then the correct option is the first one; On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

mestny [16]3 years ago
8 0

Answer:

First graph

Did it on egd :)

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