For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
Answer:
its x: x< -3
Step-by-step explanation:
ya
The most convenient method I would choose is slope-intercept form, which is y=mx+b. So, make this equation equal in terms of y.
x-y=5
subtract x from both sides
-y = 5 - x
multiply both sides by -1 so y isn't negative
y = 5 + x
5 +x is the same thing as x+5, so
y = x+5
Now, you can easily sub in any number for x and you can easily get y. Here are some points you can plot:
(0, 5), (1, 6), (2, 7), (3, 8) and the list goes on. I hope this helped!
Answer:
Find out what x should be the apply by the power of 2 then you should be good
Answer:
A
Step-by-step explanation:
3-3 is 0
0 is greater than -7
