Answer:
5/the number of socks he has
Step-by-step explanation:

We start with Left hand side
We know that csc(x) = 1/ sin(x)
So csc(2x) is replaced by 1/sin(2x)

Also we use identity
sin(2x) = 2 sin(x) cos(x)

4 divide by 2 is 2
Now we multiply top and bottom by sin(x) because we need tan(x) in our answer



We know that sinx/ cosx = tan(x)
Also 1/ sin(x)= csc(x)
so it becomes 2csc^2(x) tan(x) , Right hand side
Hence verified
Answer: 0, 4, -9
Set the equation equal to zero.
x(x - 4)(x + 9) = 0
Solve for x by setting each factor equal to zero.
The factors in the equation are x, (x - 4), and (x + 9).
x = 4
x = -9
The zeros of the function are 0, 4, and -9.
12s - 20 < 50 - 3s - 25
12s - 20 < 25 - 3s
+3s. +3s
S cancels
15s - 20 < 25
+ 20. +20
15s < 45
/15. /15
S < or equal to 3