All we need is to put this form in the vertex form f(x) = (ax+b)^2 + c
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:

Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
I hope that
helps!
Answer:
C) Revise
Step-by-step explanation:
A final draft needs to be revised before it can be published
50
(e= 10 to the power of)
6.6e-2/3.3e-4= 3.3e4/6.6e2=0.5e2= 0.5x10^2=50
Answer:
-49
8
Step-by-step explanation:
-196/4 =
-49
(3+u)^2
-------------
8
Let u=5
(3+5)^2
-------------
8
(8)^2
-------------
8
64
-----
8
8
let's firstly convert the mixed fractions to improper fractions, then divide.
![\bf \stackrel{mixed}{3\frac{1}{10}}\implies \cfrac{3\cdot 10+1}{10}\implies \stackrel{improper}{\cfrac{31}{10}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2}{5}\div \cfrac{31}{10}\implies \cfrac{2}{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{\stackrel{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{31}\implies \cfrac{4}{31}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%2010%2B1%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B31%7D%7B10%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B2%7D%7B5%7D%5Cdiv%20%5Ccfrac%7B31%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%205%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%5Ccdot%20%5Ccfrac%7B%5Cstackrel%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%2010%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%7B31%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B31%7D)