Margin of error formula:
ME = z * (Sigma) / √ n
z = 1.96 for a 95 % confidence interval;
Sigma = 3 ( the population standard deviation )
n = 500
ME = 1.96 * 3 / √500 =
= 1.96 * 3 / 22.36 =
= 5.88 / 22.36 = 0.263
Answer:
The margin error for a 95% confidence interval is 0.263.
Answer:b.y=5x
this is the answer to your question
Ishaan to have a score of 97 on the next exam have an overall average of 85
What is the mean of exam scores?
The mean of exam scores is the sum of the scores divided by the number of exams taken, more like an average of all scores
Initially, average score on 4 exams is 82
average=total score/number of exams
average score on 4 exams=82
total score =unknown=assume it is
number of exams=4
82=x/4
x=4*82
x=328
In order to have an overall average score of 85, we would sum the total score of 4 exams and the fifth exam and divide by 5 exams
85=(328+y)/5
85*5=328+y
425=328+y
y=425-328
y=97
Find out more about average on:brainly.com/question/20118982
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6 balls in the bag
1/6 getting the random color
1/6=about .16
so C
Answer:
|x - 1 |> 6,
Step-by-step explanation:
First we find the distance between the two points
-5 to 7
7 - -5 =7+5 = 12
We find 1/2 that distance
12/2 = 6
So we are looking for a greater-than inequality because we are looking for the outsides because we want a less than and a greater than
|x - b |> c,
The center is 6 to that is c
|x - b |> 6,
To find the value of b
Let x = 7
7 -b =6
b=1
|x - 1 |> 6,
We can check by using -5
|-5 - 1 |> 6,
