<h2>
Answer: 90 rabbits</h2>
<em></em>
<h3><em>
Step-by-step explanation:</em></h3>
<em>you will need 10 for every 3 rabbits so if you count in tens and three's </em>
<em>3=10</em>
<em>6=20</em>
<em>9=30</em>
<em>and so on..</em>
<em>when you get to 27 you'll be at 90 </em>
<em>27=90 </em>
<em>hope u understand :></em>
Answer:
"Variable interval" is the right solution.
Step-by-step explanation:
- A variable-interval timetable seems to be a fiber-reinforced routine where another sensitivity or reaction would be commended because an unanticipated or unstable transaction has taken place, which would be the exact reverse of either a fixed-interval routine.
- The whole such schedule results in a slow or predictable, fairly constant targeted respondents.
Answer:
-2
Step-by-step explanation:
We can find the slope of a line given two points from
m = (y2-y1)/(x2-x1)
= (-2-4)/(1--2)
= (-6)/(1+2)
=-6/3
=-2
Since this is a compound interest problem, you have to take note that the amount Catherine will get per year is not the same. It will increase per year since it is compounded. So first, we get the amount after one year. This will be 7000 x 0.04 which is 280 plus 7280. In the second year, she will get 7571 (7280 x 0.04 + 7280). In the third year, she will get 7874 (7571 x 0.04 + 7571). In the fourth year, she will get 8189 (7874 x 0.04 + 7874). And finally in the fifth year, she will get 8517 (8189 x 0.04 +8189). So after five years, she has 8517
Answer:
Outside the circle
Step-by-step explanation:
Let's first write the equation of this circle: 
, where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:
NE = 
The radius is √34, which means that r² = 34. So, our equation is:
(x + 6)² + (y + 2)² = 34
Plug in -10 for x and -7 for y:
(x + 6)² + (y + 2)² = 34
x² + 12x + 36 + y² + 4y + 4 = 34
x² + 12x + y² + 4y + 40 = 34
x² + 12x + y² + 4y + 6 = 0
(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7
Since 7 > 0, we know that H lies outside the circle.
