Answer:
$1620
Step-by-step explanation:
9% of budget = 0.09 × $18000 = $1620
Anthony spent $1620 on the family room.
The simplified form for (3x² + 2y² - 5x + y) + (2x² - 2xy - 2y² -5x + 3y) is (5x² + 0y² - 10x + 4y - 2xy).
<h3>A quadratic equation is what?</h3>
At least one squared term must be present because a quadratic is a second-degree polynomial equation. It is also known as quadratic equations. The answers to the issue are the values of the x that satisfy the quadratic equation. These solutions are called the roots or zeros of the quadratic equations. The solutions to the given equation are any polynomial's roots. A polynomial equation with a maximum degree of two is known as a quadratic equation, or simply quadratics.
<h3>How is an equation made simpler?</h3>
The equation can be made simpler by adding up all of the coefficients for the specified correspondent term through constructive addition or subtraction of terms, as suggested in the question.
Given, the equation is (3x² + 2y² - 5x + y) + (2x² - 2xy - 2y² -5x + 3y)
Removing brackets and the adding we get,
3x² + 2x² + 2y² - 2y² + (- 5x) + (- 5x) + y + 3y + (- 2xy) = (5x² + 0y² - 10x + 4y - 2xy)
To learn more about quadratic equations, tap on the link below:
brainly.com/question/1214333
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Answer:
The volume of the solid is the volume of the prism minus the volume of the cylinder.
For the cylinder, diameter = d = 4 cm
radius = d/2 = (4 cm)/2 = 2 cm
V = volume of prism - volume of cylinder
The volume of a prism is length times width times height.
The volume of a cylinder is pi times the square of the radius times the height.
V = LWH - (pi)r^2h
V = 6 cm * 6 cm * 15 cm - (pi)(2 cm)^2(15 cm)
V = 540 cm^3 - 60pi cm^3
V = (540 - 60pi) cm^3
Answer:
41
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 7 and d = 3, thus
= - 7 + (16 × 3) = - 7 + 48 = 41
F(x) = -4x + 1
g(x) = 3x + 1
A. (f + g)(x) = (-4x + 1) + (3x + 1)
(f + g)(x) = (-4x + 3x) + (1 + 1)
(f + g)(x) = x + 2
Domain: (-∞, ∞) {x|x ∈ R}
B. (f - g)(x) = (-4x + 1) - (3x + 1)
(f - g)(x) = (-4x - 3x) + (1 - 1)
(f - g)(x) = -7x
Domain: (-∞, ∞) {x|x ∈ R}
C. (f · g)(x) = (-4x + 1)(3x + 1)
(f · g)(x) = -4x(3x + 1) + 1(3x + 1)
(f · g)(x) = -4x(3x) - 4x(1) + 1(3x) + 1(1)
(f · g)(x) = -12x² - 4x + 3x + 1
(f · g)(x) = -12x² - x + 1
Domain: (-∞, ∞) {x|x ∈ R}
D. (f ÷ g)(x) = (-4x + 1) ÷ (3x + 1)
Domain: (-∞, ⁻¹/₃) U (⁻¹/₃, ∞) {x|x ≠ ⁻¹/₃}
