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Orlov [11]
3 years ago
13

The Alliance Corp. expects to sell the following number of units of copper cables at the prices indicated, under three different

scenarios in the economy. The probability of each outcome is indicated. Outcome Probability Units Price A 0.50 295 $ 34 B 0.30 510 49 C 0.20 790 59 What is the expected value of the total sales projection?
Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer:

E(x) = 21834

Step-by-step explanation:

Given

The above data

Required

Determine the expected value E(x)

E(x) is calculated as thus;

E(x) = \sum xf(x)

Where f(x) represents the total sale of each outcome;

For A:

f(x) = 295 *34

f(x) = 10030

For B:

f(x) =510 *49

f(x) =24990

For C:

f(x) = 790 *59

f(x) = 46610

Hence, E(x):

E(x) = 0.5 * 10030 + 0.30 * 24990 + 0.20 * 46610

E(x) = 21834

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Pls help with these math problems
katrin2010 [14]

Answer:

Step-by-step explanation:

1)

First we add what we know for y into the second equation.

5x - 4(x +2)= -3

From there, we simplify it

5x-4x-8= -3

x-8=-3

Now we get the x on its own

x=5

and now we add x=5 into the first equation that we had and simplify to find y

y=5+2

y=7

So the answer is x=5, y=7 or (5,7)

2)

For this one we do the same thing as with 1.

Add what we know for y (bottom equation) to the top equation

3x-8(x-8)=24

Now we simplify

3x-8x+64=24

-5x+64=24

And now solve for X

-5x=-40

x=8

And then substitute x=8 to find y

y=8=8

y=0

So the answer is x=8, y=0 or (8,0)

5 0
3 years ago
Solve this question
Art [367]
50 Dollars For The Member-Ship

2 Dollars For The Class (C)

Y=Total (unknown because you dont know how may classes)

Y=50(C)


7 0
4 years ago
H=7+44t-16^2
djyliett [7]

Answer:

t_1\approx2.18

t_2\approx0.57

Step-by-step explanation:

h=7+44t-16t^2

27=7+44t-16t^2

0=-20+44t-16t^2

0=-16t^2+44t-20

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

t=\frac{-44\pm\sqrt{44^2-4(-16)(-20)}}{2(-16)}

t=\frac{-44\pm\sqrt{1936-1280}}{-32}

t=\frac{-44\pm\sqrt{656}}{-32}

t=\frac{-44\pm4\sqrt{41}}{-32}

t=\frac{11}{8}\pm\frac{\sqrt{41}}{8}

t_1\approx2.18

t_2\approx0.57

5 0
2 years ago
A Ferris wheel is 20 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position
pantera1 [17]

Answer:

233.48s  

3.84 min

Step-by-step explanation:

In order to solve this problem, we can start by drawing what the situation looks like. See attached picture.

We can model this situation by making use of a trigonometric function. Trigonometric functions have the following shape:

y=A cos(\omega t+\phi)+C

where:

A= amplitude =-20m because the model starts at the lowest point of the trajectory.

f= the function to use, in this case we'll use cos, since it starts at the lowest point of the trajectory.

t= time

\omega= angular speed.

in this case:

\omega=\frac{2\pi}{T}

where T is the period, in this case 6 min or

6min(\frac{60s}{1min})=360s

so:

\omega=\frac{2\pi}{360}

\omega = \frac{\pi}{160}

and

\phi= phase angle

C= vertical shift

in this case our vertical shift will be:

2m+20m=22m

in this case the phase angle is 0 because we are starting at the lowest point of the trajectory. So the equation for the ferris wheel will be:

y=-20 cos(\frac{\pi}{180}t)+22

Once we got this equation, we can figure out on what times the passenger will be higher than 13 m, so we build the following inequality:

-20 cos(\frac{\pi}{180}t)+22>13

so we can solve this inequality, we can start by turning it into an equation we can solve for t:

-20 cos(\frac{\pi}{180}t)+22=13

and solve it:

-20 cos(\frac{\pi}{180}t)=13-22

-20 cos(\frac{\pi}{180}t)=-9

cos(\frac{\pi}{180}t)=\frac{9}{20}

and we can take the inverse of cos to get:

\frac{\pi}{180}t=cos^{-1}(\frac{9}{20})

which yields two possible answers: (see attached picture)

so

\frac{\pi}{180}t=1.104 or \frac{\pi}{180}t=5.179

so we can solve the two equations. Let's start with the first one:

\frac{\pi}{180}t=1.104

t =1.104(\frac{180}{\pi})

t=63.25s

and the second one:

\frac{\pi}{180}t=5.179

t=5.179(\frac{180}{\pi})

t=296.73s

so now we can build our possible intervals we can use to test the inequality:

[0, 63.25]  for a test value of 1

[63.25,296.73] for a test value of 70

[296.73, 360] for a test value of 300

let's test the first interval:

[0, 63.25]  for a test value of 1

-20 cos(\frac{\pi}{180}(1))+22>13

2>13 this is false

let's now test the second interval:

[63.25,296.73] for a test value of 70

-20 cos(\frac{\pi}{180}(70))+22>13

15.16>13 this is true

and finally the third interval:

[296.73, 360] for a test value of 300

-20 cos(\frac{\pi}{180}(300))+22>13

12>13 this is false.

We only got one true outcome which belonged to the second interval:

[63.25,296.73]

so the total time spent above a height of 13m will be:

196.73-63.25=233.48s

which is the same as:

233.48(\frac{1min}{60s})=3.84 min

see attached picture for the graph of the situation. The shaded region represents the region where the passenger will be higher than 13 m.

3 0
3 years ago
Mitt ate 24 peanuts. this represents 75% of the bag of peanuts. How many peanuts were originally in the bag?
inessss [21]
Part/whole = percent/100
REMEBER THIS: 100 WILL ALWAYS BE THE TOTAL OF THE PERCENT!!!!!!!
So you multiply 24 ˣ 100 =2400/75 = 32
8 0
3 years ago
Read 2 more answers
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