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3 years ago

Geometry math question no Guessing and Please show work

Mathematics

2 answers:

Annette [7]3 years ago

7 0

If the quadrants are disposed like this pattern:

I. II.

III. IV.

And the y- achsis is in middle of I./II. and III./IV.

then parallel of IV. is III

sergiy2304 [10]3 years ago

6 0

the answer is D.

I dont know how to add work for a question like this, however, I know how I'd show work....

Draw a graph and stick a point in the IV quadrant and label it "original". Then next to it, draw another graph and stick a point in the III quadrant and label it "reflection"

TIP: if you do that, make sure the points are in the same location in each quadrant

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3 years ago

Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's

Tom [10]

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

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the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer

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3 years ago

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rjkz [21]

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3 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

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2 years ago