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deff fn [24]
3 years ago
11

Find the nth term of: 11, 18, 37, 74, 135

Mathematics
1 answer:
storchak [24]3 years ago
6 0
The nth term is 6n^2-11n+16
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Choose the graph that matches the following system of equations: 2x + y = −1 3x + 2y = −6
Karolina [17]
Hi! You don't actually need to graph this nor find the intersection in order to know the answer. Through the process of elimination we can rule out incorrect answers.

Firstly, we express both equations with y on the left hand side since all choices are in that form:

y=-2x-1
y=- \frac{3}{2}x-3

Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.

You can verify if the point of intersection provided in option b is true by plugging in the values of x and y to both equations (you will find that it is indeed true).

ANSWER: b. <span>picture of coordinate plane with line y equals negative 2x minus 1 and line y equals negative 3 halves x minus 3. They intersect at 4, negative 9.</span>
4 0
3 years ago
Read 2 more answers
Find an equation of the tangent plane to the surface z=ln(x-6y) at the point(7,1,0)
expeople1 [14]

The tangent plane equation of tangent plane is

z = x - 6y -1

This is further explained below.

What is the equation of the tangent plane to the surface z=ln(x-6y) at the point(7,1,0)?

Generally, Given surface is z = ln(x − 6y) ,

Given point is (x_0, y_0 , z_0) = (7, 1, 0)

partially differentiating with respect to x

== >zx = [1/(x - 6y)] (1) = 1/(x - 6y)

zx (7 , 1 , 0) = 1/(7 - 6(1)) = 1

Partially differentiating with respect to y

zy = [1/(x - 6y)] (-6)

zy = -6/(x - 6y)

zy(7 , 1 , 0) = -6/(7 - 6(1)) = -6

Equation of tangent plane is z - z_0 = zx(x -x_0) + zy(y - y_0)

z - 0 = 1(x - 7) + (-6)(y - 1)

z = x - 7 -6y + 6

z = x - 6y -1

In conclusion, equation of tangent plane is z = x - 6y -1

Read more about the tangent plane

brainly.com/question/10542585

#SPJ4

8 0
2 years ago
Which description of the vector shown is correct ?
BartSMP [9]

Answer:

(B) The magnitude is 7sqrt2, and the direction angle is approximately 135 degrees.

Step-by-step explanation:

From the figure, the coordinate of the tail of the vector,

(x_1,y_1)=(3,-6).

The coordinate of the head of the vector,

(x_2,y_2)=(-4,1).

The magnitude of a vector is the length between the head and tail of the vector.

By using the distance formula,

the magnitude of the vector = \sqrt{(1-(-6))^2+(-4-3)^2}

=\sqrt{(7^2+(-7)^2}\\\\=\sqrt{98}\\\\=7\sqrt{2}

Now, let \theta be the angle made by the vector with the positive direction of the x-axis, so

\tan\theta = \frac{y_2-y_1}{x_2-x_1}\\\\\Rightarrow \tan\theta = \frac{1-(-6)}{-4-3}=\frac{7}{-7}=-1 \\\\\Rightarrow \theta = \tan^{-1}(-1) \\\\\Rightarrow \theta =\pi- \tan^{-1}1 \\\\\Rightarrow \theta = \pi-\frac{\pi}{4} \\\\\Rightarrow \theta =\frac{3\pi}{4} \\\\\Rightarrow \theta = 135 ^{\circ}.

So, the magnitude of the vector is 7\sqrt 2 which makes 135 ^{\circ} with the positive direction of the x-axis.

Hence, option (B) is correct.

8 0
3 years ago
Read 2 more answers
Please I need help quick
mafiozo [28]
The ratios are both identical

sin x = perpendicular/hypotenuse = 3/5
cosy = base/hypotenuse = 3/5
4 0
3 years ago
Read 2 more answers
Please help me out!!!!
LuckyWell [14K]

Answer:

the value for x is

11 \sqrt{3}

and the value for y is 11 on the triangle problem we use sin60 to find x and we use tan60 to find y

7 0
3 years ago
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