|AC| = 2|DE|
⇒
4x - 2 = 2(x + 6) = 2x + 12
2x = 14
x = 7
⇒
|AC| = 26
Answer: g(x) has the smallest possible y-value of -3
<u>Step-by-step explanation:</u>
f(x) = 3ˣ - 3 <em>This is an exponential graph shifted down three units. So, it has an asymptote at y = -3, which means it approaches -3 but does not touch it.</em>
Range: y > 3 (-3, ∞)
g(x) = 7x² - 3
⇒ g(x) = 7(x - 0)² - 3 <em>This is a parabola with vertex at (0, -3) </em>
Range: y ≥ 3 [-3, ∞)
Lets change "16" by its to 16/1 .. since nothing can't help support 16 by itself when it is going into 7/10
Now that we change that ... your problem becomes 7/10 × 16/1
7/10 × 16/1 = 11 1/5
Because
7(16) / 10(1) = 112/10
Now lets go. to how we solve the for the answer
112/10 = 11 1/5
☺
