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Arlecino [84]
3 years ago
9

A Geometry student says I got lost in that lesson I wrote down that AD/AB eQUALS AC/ab but I have no idea where comes from

Mathematics
1 answer:
Grace [21]3 years ago
7 0

Answer:

AD/AB = AB/AC

Step-by-step explanation:

If we take two triangules in that figure: ABC and ABD, both are triangles rectangles. We need to use the definition of cosine, with the angle in th A corner, we called ∅.

For the ABC triangle: cos(∅) = adjacent cathetus/hypotenuse = AD/AB

For the ABD triangle: cos(∅) = adjacent cathetus/hypotenuse = AB/AC

Then:

cos(∅) = AD/AB = AB/AC

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jack wants to paint his walls. two walls are 12 ft by 8 ft and two walls are 10 ft by 8 ft. what is the area to be painted? if o
Ksivusya [100]

Answer:

352 ft (squared)  , he will need 12 paint cans

Step-by-step explanation:

Two 12 by 8ft walls = 192 ft in area, Two 10 by 8ft walls = 160 ft in Area, that equals 352 ft total, 352/30=11.73 repeated, round up to 12

4 0
2 years ago
Type the slope-intercept equation
natulia [17]

Answer:

y= -2x +1

Step-by-step explanation:

<u>slope- intercept form</u><u>:</u>

y= mx +c, where m us the gradient and c is the y-intercept.

Let's find the value of m first using the gradient formula.

Gradient= \frac{y1 - y2}{x1 - x2}

m =  \frac{ - 3 - 3}{2 - ( - 1)}  \\ m =  \frac{ - 6}{2 + 1}  \\ m =  \frac{ - 6}{3}  \\ m =  - 2

y= -2x +c

To find the value of c, substitute a pair of coordinates.

When x= -1, y=3,

3= -2(-1) +c

3= 2 +c

c= 3 -2

c= 1

Thus the equation of the line is y= -2x +1.

4 0
3 years ago
Classify by degree and number of terms, in that order<br><br> 5x^2-2x+3
zmey [24]

Answer:

no tiene respuesta perdon

6 0
3 years ago
Find the volume of the triangular prism that has a width of 4in, and length of 8in and a hight of 2in
Stolb23 [73]

Answer:

32

Step-by-step explanation:

3 0
3 years ago
If you can solve it.Thanks in advance
vivado [14]

Answer:

f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}

Step-by-step explanation:

we have

f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}

g(x)=\frac{1}{x^{2}+1}

we know that

In the function

f(g(x))

The variable of the function f is now the function g(x)

substitute

f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}

f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}

4 0
3 years ago
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