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3 years ago

If A=0 and E=1, what is the value of C

Mathematics

1 answer:

daser333 [38]3 years ago

7 0

Answer:

C=2

Step-by-step explanation:

(26/3 so remainder =2) place of C in alphabet = 3

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The price of a mat is x USD from the start. Write an expression for the price:

Serga [27]

Answer:

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2 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

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3 years ago

Math question please show work due today last day to submit Assignments or I fail please help

Aleksandr [31]

Answer:

The polygons are similar.

Step-by-step explanation:

By definition, the corresponding sides and angles of similar polygons must be in some constant proportion.

Therefore, we can find the ratio between corresponding sides to see if that ratio is maintained.

The side marked 3 cm in the smaller figure corresponds with the side marked 3.75 cm in the larger figure. This proportion is $\frac{3}{3.75}$ .

The side marked 5 in the smaller figure corresponds with the side marked 6.25 cm in the larger figure. This proportion is $\frac{5}{6.25}$ .

If these polygons are similar, these proportions must be equal.

$\frac{3}{3.75}=\frac{5}{6.25},\\0.8=0.8\:\checkmark$

Checking, we see that these proportions are equal, and therefore the polygons are similar.

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2 years ago

-9a + 11ad - 35a + ad

34kurt

-9a + 11ad - 35a + ad = -44a + 12ad

hope this helps

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3 years ago

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Lelechka [254]

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3 years ago