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Leto [7]
3 years ago
12

Write a linear equation in slope intercept form to model a tree 4 feet tall the grows 3 inches per year

Mathematics
1 answer:
Hoochie [10]3 years ago
7 0
Y = 3x + 48  where x is your number of years. I got 48 by multiplying 4 and 12 since there are 12 inches in a foot. (:
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Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
In triangle abc, AC=15 BC=11 and m
Oksana_A [137]

Answer: 10

Step-by-step explanation:

In a right angle triangle

Hypothenus ^2= opposite ^2+ adjacent ^2

According to a diagram below

Hypothenus =15

Opposite =?

Adjacent =11

Substitute for the values

15^2=11^2+opp^2

Opp^2=15^2-11^2

0pp^2= 225-121

Opp2=104

Opp= square root of 104

Opp= 10.2

Opp= ~10

3 0
3 years ago
(-4)-(-2)-{(-5)-[(-7)+(-3)-(-8)]}
aleksklad [387]

Answer:

is one

Step-by-step explanation:

its just one i know trust me

7 0
2 years ago
Expression of "Eight less than half the sum of 4 and k” into symbol
jolli1 [7]

Answer:

\frac{4+k}{2} -8

Step-by-step explanation:

We're going to have to work backwards.

The sum of 4 and k is 4+k.

Half is simply that divided by 2.

\frac{4+k}{2}

Now, we'll subtract 8 from it.

\frac{4+k}{2} -8

Bam!

7 0
3 years ago
Which of the following is equivalent?
tia_tia [17]

Answer:

0.4

Step-by-step explanation:

Yeetyettyeteheheyehe

6 0
3 years ago
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