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netineya [11]
3 years ago
6

If the cubic container had a volume of 1,728 in³, what would its dimensions be?

Mathematics
2 answers:
sineoko [7]3 years ago
6 0

Answer:

12 inches × 12 inches × 12 inches

Step-by-step explanation:

Cube volume is s^3

s^3=1728

s=\sqrt[3]{1728}

s=12

monitta3 years ago
5 0

Answer:

Dimensions = 12 inches

Step-by-step explanation:

Volume -of-a-cube = l^{3} \\V =l^{3}\\1728=l^{3}\\Cube-root-both-sides -of-the-equation.\\\sqrt[3]{1728} =\sqrt[3]{l^{3}} \\l = 12 inches

Note , L= Value of one side

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Answer:-2.3

Step-by-step explanation:

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2 years ago
1.the graph of y = x² is moved five units upward
KonstantinChe [14]

Answer:

I guess that we want to find the equation for each case.

First, let's define the translations:

Horizontal translation.

For a function f(x), an horizontal translation of N units is written as:

g(x) = f(x + N)

if N > 0, the translation is to the left

if N < 0, the translation is to the right.

Vertical translation:

For a function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

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if N < 0, the translation is downwards.

Now that we know these, we can find the equations for each case:

1. the graph of y = x² is moved five units upward

the graph is given by a vertical translation of 5 units upward.

y = x^2 + 5

2 the graph of y = 5x² is moved six units to the left

this is:

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3: the graph of y = -2x² is moved seven units downward

this is:

y = -2x^2 - 7

4: the graph of y = -x² is moved two units to the left and four units downward

now we have two translations, first 4 units to the left and then 4 units downwards, this gives:

y = -(x + 4)^2 - 4

5: the graph of y = -3x² is moved two units to the right

Remember that to move the graph to the right, we need to have N negative, then:

y = -3(x - 2)^2

8 0
2 years ago
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Answer:

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Step-by-step explanation:

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Answer:

B

Step-by-step explanation:

on edge

3 0
2 years ago
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