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3 years ago

Y varies directly with x2 and y = 72 when x = 3.

Mathematics

1 answer:

Andrews [41]3 years ago

7 0

I think the problem is work this way because y is equal to 72 and x is 3 you just multiply 72(3)2=432

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Prove the identity 2csc2x=csc^2xtanz

Verizon [17]

Step-by-step explanation:

Consider the LHS, after the 5th step, consider the RHS

$2 \csc(2x) = \csc {}^{2} (x) \tan(x)$

$2 \frac{1}{ \sin(2x) } = \csc {}^{2} (x) \tan(x)$

$2 \times \frac{1}{2 \sin(x) \cos(x) } = \csc {}^{2} (x) \tan(x)$

$\frac{1}{ \sin(x) \cos(x) } = \csc {}^{2} (x) \tan(x)$

$\csc(x) \sec(x) = \csc {}^{2} (x) \tan(x)$

Consider the RHS

$\csc(x) \sec(x) =( 1 + \cot {}^{2} (x) ( \tan(x))$

$\csc(x) \sec(x) = \tan(x) + \cot(x)$

$\csc(x) \sec(x) = \frac{ \sin(x) }{ \cos(x) } + \frac{ \cos(x) }{ \sin(x) }$

$\csc(x) \sec(x) = \frac{1}{ \sin(x) \cos(x) }$

$\csc(x) \sec(x) = \csc(x) \sec(x)$

7 0

2 years ago

If I have an equation in which x = pounds, and y = total cost, can I substitute quarts into the equation

Colt1911 [192]

Answer:

Yes, you can

Step-by-step explanation:

As a point of reference, assume the equation is:

$y = 5x$

Where

$y = total\ cost$

and

$x = pounds$

In standard unit of conversion:

$1\ pound = 0.4793\ quart$

So:

$x\ pounds = 0.4793x\ quart$

Substitute 0.4793x for x in $y = 5x$

$y = 5 * 0.4793x$

$y = 2.3965x$

The above equation is the equivalent of $y = 5x$ in quarts

<em>So, irrespective of what the equation is, you can always substitute quarts into the equation.</em>

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3 years ago

If the rectangle ABCD rotated 90 degrees clockwise, which coordinate

pashok25 [27]

Answer:

The answer will be A) A'(4,3)

Step-by-step explanation:

90 degrees will send the rectangle to Quadrant 1, the rectangle itself has also been rotated so by rotating the rectangle 90 degrees and putting it in place for quadrant 1, it should give you the answer.

(You can also rotate the image)

3 0

3 years ago

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What is the reference angle for 11pi/6? Explain your thinking.

il63 [147K]

First we need to see in which quadrant 11pi/6 lies And it lies in fourth quadrant. And to find the reference angle in the fourth quadrant, we need to subtract the given angle from 2 pi . For e.g if the angle is 5pi/3, then the reference angle is 2pi - (5pi/3) = pi/3 .

So for the given question, reference angle of 11pi/6 is

$2 \pi - \frac{11 \pi}{6} = \frac{ \pi}{6}$

And that's the required reference angle .

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3 years ago

Karoline borrows lunch money from Roselia for 4 days in a row. Each lunch costs $8.

photoshop1234 [79]

Answer:

Step-by-step explanation:

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1 year ago

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