Answer:
Disrupts communication systems
Composed of charged particles
travels at about 400 km/s
Potassium is placed where it is based on its properties and it's reactivity. It's also placed there based on it's atomic number.
Given :
Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .
To Find :
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .
Solution :
By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
So , volume of solution does not matter .
Moles of oxygen , 
.
Now , molecule of CO contains 1 mole of C .
So , moles of C is also 0.167 mole .
Mass of carbon , 
.
Therefore , mass of carbon is 2 grams .
Hence , this is the required solution .
<u>Answer</u>:
By tracking oxidation numbers we can identify the number electron in the atom
<u>Explanation</u>:
Tracking of electrons helps us to know when and how many electrons get transferred from one atom to other atom . Oxidation referred as the “loss of one or more electrons” by an atom. When the oxidation number of an element increases, there is a loss of electrons and that element is being oxidized. Oxidation numbers are usually written with the sign (+plus or −minus) followed by the magnitude, which is the opposite of charges on ions. In their elemental stage oxidation number of an atom is zero.
Answer:
Q = 10.10059 KJ
Explanation:
Given data:
Amount of water = 13.0 g
Initial temperature = 52.5°C
Final temperature = 238.2°C
Heat required to convert it into steam = ?
Solution:
Specific heat capacity of water is 4.184 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 238.2°C - 52.5°C
ΔT = 185.7 °C
by putting values,
Q = 13.0 g × 4.184 J/g.°C × 185.7 °C
Q = 10100.59 J
Jolue to Kj:
10100.59j × 1 KJ/1000 J
Q = 10.10059 KJ
