Answer : The molarity of the resulting ammonia solution is, 0.89 M
Explanation :
The balanced chemical reaction is:
First we have to calculate the moles of nitrogen gas.
As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.
As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas
So, 50.0 L volume of nitrogen gas present in moles of nitrogen gas
Thus, the moles of nitrogen gas is 2.23 moles.
Now we have to calculate the moles of ammonia gas.
From the reaction, we conclude that
As, 1 mole of react to give 2 mole of
So, 2.23 moles of react to give
moles of
Now we have to calculate the molarity of the resulting ammonia solution.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molarity of the resulting ammonia solution is, 0.89 M
