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Katarina [22]
3 years ago
11

For the question(s) that follow, consider the following equation. Mg3N2(s) + 6H2O(l) → 3Mg (OH)2(s) + 2NH3(g) What is the correc

t form of the conversion factor needed to convert the number of moles of H2O to the number of moles of NH3 produced?
Chemistry
1 answer:
zhenek [66]3 years ago
3 0

Answer:

2/6

Explanation:

In a balanced chemical equation as:

aA + bB → cC + dD

Where coefficients of reaction relates the number of moles of substances that are involved in the reaction. In the reaction:

Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)

Per mole of Mg₃N₂(s) and per 6 moles of H₂O you will produce 3 moles of Mg(OH)₂(s) and 2 moles of NH₃(g).

To convert moles of H₂O to moles of NH₃ you can use:

X moles of H₂O ₓ (2 moles NH₃ / 6 moles of H₂O)

That means conversion factor to convert the number of moles of water to number of moles of ammonia is <em>2/6</em>.

<em>-It is important to say that obtention of conversion factor requires, in the first, the balanced chemical equation-</em>

<em />

I hope it helps!

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