All categories

3 years ago

What is simplest level at which life may exist

Chemistry

2 answers:

just olya [345]3 years ago

8 0

The simplest level at which life may exist is a cell

7nadin3 [17]3 years ago

5 0

A cell or if u wana go deeper is organells

You might be interested in

What is an ecosystem. A.It is a single plant and a single animal that live in given area B. it is a community of plants, animals

gavmur [86]

Answer:

B. it is a community of plants,animals and there physical surrounding.

8 0

2 years ago

Fill in the blank Cells break down sugar and release ___________ into the plant.

katrin2010 [14]

Answer:

oxygen

Explanation:

8 0

2 years ago

Which of the following Kb values represents the strongest base?

alexandr402 [8]

Answer:

D. Kb = 1.8 × 10⁻⁵

Explanation:

The strongest base has the largest Kb value.

The largest Kb value has the smallest negative exponent.

So, the strongest base has Kb = 1.8 × 10⁻⁵.

4 0

3 years ago

Read 2 more answers

What happens during all chemical changes?

3241004551 [841]

Answer: Option (B) is the correct answer.

Explanation:

A change which brings change in composition of atoms of a substance to result in the formation of new substances is known as a chemical change.

Therefore, in a chemical change new substances are formed which have different properties as compared to their reactants.

For example, $2Na + Cl_{2} \rightarrow 2NaCl$

Thus, we can conclude that during all chemical changes atoms rearrange to form new substances.

7 0

3 years ago

Read 2 more answers

1.2 kg of aluminum at 20oC is added to 1.5 kg of water at 80oC. After the system reaches thermal equilibrium, what is its final

Lubov Fominskaja [6]

Answer:

The final temperature is 71.19 °C

Explanation:

Step 1: Data given

Mass of aluminium = 1.2 kg = 1200 grams

Temperature of aluminium = 20.0 °C

Specific heat of aluminium = 0.900 J/g°C

Mass of water = 1.5 kg = 1500 grams

Temperature of water = 80.0 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the final temperature

heat gained = heat lost

Q(aluminium) = - Q(water)

Q = m*c*ΔT

m(aluminium) * c(aluminium) * ΔT(aluminium) = - m(water) * c(water) * ΔT(water)

⇒ with mass of aluminium = 1200 grams

⇒ with specific heat of aluminium = 0.900 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 20.0 °C

⇒ with mass of water = 1500 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 80.0°C

1200 * 0.900 * (T2-20.0°C) = -1500 * 4.184 * (T2 - 80.0°C)

1080 * (T2 - 20.0°C) = -6276 * (T2 - 80.0°C)

1080 T2 - 21600 = -6276T2 + 502080

7356T2 = 523680

T2 = 71.19 °C

The final temperature is 71.19 °C

8 0

3 years ago