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horrorfan [7]
3 years ago
6

What is simplest level at which life may exist

Chemistry
2 answers:
just olya [345]3 years ago
8 0
The simplest level at which life may exist is a cell
7nadin3 [17]3 years ago
5 0
A cell or if u wana go deeper is organells
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Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to
murzikaleks [220]

Answer:

Force used by fire extinguisher = 60 N

Explanation:

Given:

Mass of skateboard with fire extinguisher = 50 kg

Acceleration of fire extinguisher = 1.2 m/s²

Find:

Force used by fire extinguisher = ?

Computation:

⇒ Force = Mass × Acceleration

⇒ Force used by fire extinguisher = Mass of skateboard with fire extinguisher × Acceleration of fire extinguisher

⇒ Force used by fire extinguisher = 50 kg × 1.2 m/s²

⇒ Force used by fire extinguisher = 60 N

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3 years ago
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Accuracy vs. Precision
Oksi-84 [34.3K]

Answer:

Accuracy is the closeness to the specific target and precision is the closeness of the measurements to each other.

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Aleks04 [339]

Explanation:

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6 0
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Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT
Andru [333]

Answer:

6.14\cdot 10^{-6}

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

K_{eq} = \frac{[ADP][Pi]}{ATP}

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

\Delta G^o = -RT ln K_{eq}

From here, rearrange the equation to solve for K:

K_{eq} = e^{-\frac{\Delta G^o}{RT}}

Now we know from the initial equation that:

K_{eq} = \frac{[ADP][Pi]}{ATP}

Let's express the ratio of ADP to ATP:

\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}

Substitute the expression for K:

\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}

Now we may use the values given to solve:

\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}

7 0
3 years ago
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